Answer:
that is what your polygon should look like
Step-by-step explanation
Write an equation to match each statement. Then solve. #1) 8 less than a number x is -12. #2) 15 more than a number k is 2. #3)
A number divided by -7 is -20. #4) The product of 5/8 and a number is -20.
1 answer:
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Answer:
Step-by-step explanation:
The formula of an area of a circle:
<em>r</em> - radius
We have the endpoints of a diameter of a circle.
The formula of a distance between two points:
Substitute the coordinates of the given points A(3, 4) and B(10, 4):
Therefore we have the length of the diameter: <em>d = 7</em>
We know: <em>d = 2r.</em> Therefore
Substitute to the formula of an area:
<em>There is no such answer in the answers to choose.</em>
<em>Apparently you have some error in the coordinates of the endpoints.</em>
The mean, median and mode are measures of central tendency, that is they tend to indicate the location middle of the data
Required values;
(a) The performance for the week for Park Street
- Revenue is <u>Q₂ < $7,500 < Q₃</u>
- The sales for the week is better than <u>72.91%</u> of all sales
The performance for the week for Bridge Road
- Revenue; <u>Q₂ < $7,100 < Q₃</u>
- The sale for the week is better than <u>59.87%</u> of all sales
(b) The mean is <u>$3611</u>
The median is $<u>3,600</u>
The standard deviation is $<u>3250</u>
The Interquartile range is $<u>6075</u>
Reason:
The table of values that maybe used to find a solution to the question is given as follows;
(a) Park Street revenue = $7,500
Bridge Road's revenue = $7,100
The two stores sold close to but below the 75th percentile
Bridge Road revenue;
The z-score is given as follows;
From the Z-Table, we have;
The percentile= 0.7291
- Therefore, the sale for the week for Park Street is better than <u>72.91%</u> of all the sales
Park Street revenue;
The z-score is given as follows;
From the Z-Table, we have;
The percentile = <u>0.5987</u>
- Therefore, the sale for the week is better than <u>59.87 %</u> of all the sales
(b) Given that the operating cost is $3,000, frim which we have;
The subtracted value is subtracted from the mean and median to find the new value
Profit = The revenue - Cost
New mean = 6611 - 3000 = 3611
- The new mean = <u>$3,611</u>
The new median = 6600 - 3000 = 3600
- The new median = <u>$3,600</u>
The standard deviation and the interquartile range remain the same, therefore, we have;
- The standard deviation = <u>$3,580</u>
The interquartile range = 9675 - 3600 = 6075
- The interquartile range = <u>6075</u>
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