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Reptile [31]
2 years ago
11

What is the product of (2p + 7)(3p2 + 4p – 3)?

Mathematics
2 answers:
Nitella [24]2 years ago
7 0
The answer is <span>C=6p3 + 29p2 + 22p – 21</span>

To calculate the product, we need to multiply each member of each multiplier:
(2p + 7)(3p2 + 4p – 3) = 2p · 3p² + 2p · 4p + 2p · -3 + 7 ·3p² + 7 · 4p + 7 · -3
                                    =    6p³     +     8p²    -     6p    + 21p²   +  28p   -     21
                                    = 6p³ + 8p² + 21p² + <span>28p - 6p -21
                                    = </span>6p³ + 29p² + 22p - 21

Therefore, the product of (2p + 7)(3p2 + 4p – 3) is 6p³ + 29p² + 22p -21
Inga [223]2 years ago
7 0

Answer:c

Step-by-step explanation:

your welcome

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Step-by-step explanation:

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3/13

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Answer:

First option:  3x^2-5x=-8

Second option: 2x^2=6x-5

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Step-by-step explanation:

Rewrite each equation in the form ax^2+bx+c=0 and then use the Discriminant formula for each equation. This is:

D=b^2-4ac

1) For 3x^2-5x=-8:

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Then:

D=(-5)^2-4(3)(8)=-71

Since D this equation has no real solutions, but has two complex solutions.

2) For 2x^2=6x-5:

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Then:

D=(-6)^2-4(2)(5)=-4

Since D this equation has no real solutions, but has two complex solutions.

3) For 12x=9x^2+4:

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Then:

D=(-12)^2-4(9)(4)=0

Since D=0 this equation has one real solution.

4) For -x^2-10x=34:

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Then:

D=(-10)^2-4(-1)(-34)=-36

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Answer:

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Step-by-step explanation:

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2 years ago
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