What is the product of (2p + 7)(3p2 + 4p – 3)?
2 answers:
The answer is <span>C=6p3 + 29p2 + 22p – 21</span>
To calculate the product, we need to multiply each member of each multiplier:
(2p + 7)(3p2 + 4p – 3) = 2p · 3p² + 2p · 4p + 2p · -3 + 7 ·3p² + 7 · 4p + 7 · -3
= 6p³ + 8p² - 6p + 21p² + 28p - 21
= 6p³ + 8p² + 21p² + <span>28p - 6p -21
= </span>6p³ + 29p² + 22p - 21
Therefore, the product of (2p + 7)(3p2 + 4p – 3) is 6p³ + 29p² + 22p -21
Answer:c
Step-by-step explanation:
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