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grandymaker [24]
3 years ago
7

How do you do simple algebra

Mathematics
1 answer:
n200080 [17]3 years ago
8 0
Know the order of operations. However, one of the trickiest things about solving an algebra<span> equation as a beginner is knowing where to start. Luckily, there's a specific order for solving these problems: first </span>do<span> any math operations in parentheses, then </span>do<span> exponents, then multiply, then divide, then add, and finally subtract</span>
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pictured below are stacks of solid cubes. determine the number of cubes in the stack and the number of faces glued together.
Iteru [2.4K]

Solution

For this case we need to find the number of cubes in the stack given so then we can do this:

The first line present 5 cubes

The second line present 5 cubes

And the last line we got:

10 cubes

Then the total of cubes are:

10 +5+5 = 20 cubes

If we need to find the number of faces we can do the following:

5+ 4+ 4+4 +4 +1 + (5+4+4+4+4+1 ) + (5+4+4+4+4+1 ) + (5+ 4+4+4 +4 )

And solving we got:

22+22+ 22+21= 87

5 0
1 year ago
Which statement is true about the domain of y = 3(2^-x)? Explain.
SVEN [57.7K]
We want to determine the domain of {y=3 \cdot 2^{-x}=3 \cdot ({2^{-1}})^x=3 \cdot ({ \frac{1}{2}})^x

any function of the form y=f(x)=a \cdot b^x is called an "exponential function",
the only condition is that b is positive and different from 1, and a is a nonzero real number.

The domain of such functions is all real numbers.

That is for any x, the expression <span>3(2^-x) "makes sense".



Answer: </span><span>The domain is all real numbers</span>
8 0
3 years ago
Given that MN = 5, NO = 12, and MO = 13, find cos O.
Galina-37 [17]

Answer:

12/13

Step-by-step explanation:

Given that MN = 5, NO = 12, and MO = 13, find cos O.

Since the reference angle is P, hence;

MN is the opposite = 5

MO is the hypotenuse = 13 (longest side)

NO is the adjacent = 12

Cos O = adj/hyp

Substitute the given values

Cos O = 12/13

Hence the value of Cos O is 12/13

8 0
3 years ago
Factor:<br> 4x^2+4xy−288y^2
Sonja [21]
4x^2+4xy-288y^2=\\&#10;4(x^2+xy-72y)=\\&#10;4(x^2+9xy-8xy-72y)=\\&#10;4(x(x+9y)-8y(x+9y))=\\&#10;4(x-8y)(x+9y)
7 0
3 years ago
Using the compensation strategy. 4,153+2,988
makvit [3.9K]
4,153+2,988
-12 +12
4,141+3,000

3,000+4,000=7,000
7,000+141=7,141
5 0
3 years ago
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