X = -3.
The distance from p(-9, 0, 0) is
d = sqrt((x+9)^2 + y^2 + z^2)
The distance from q(3,0,0) is
d = sqrt((x-3)^2 + y^2 + z^2)
Let's set them equal to each other.
sqrt((x+9)^2 + y^2 + z^2) = sqrt((x-3)^2 + y^2 + z^2)
Square both sides, then simplify
(x+9)^2 + y^2 + z^2 = (x-3)^2 + y^2 + z^2
x^2 + 18x + 81 + y^2 + z^2 = x^2 - 6x + 9 + y^2 + z^2
18x + 81 = - 6x + 9
24x + 81 = 9
24x = -72
x = -3
So the desired equation is x = -3 which defines a plane.
Answer:
a = 0
Step-by-step explanation:
4(a-2) = 2(a-4) + 2a
4a - 8 = 2a - 8 + 2a
4a - 2a - 2a = -8 + 8
0 = 0
25
X x 5 = 125
125/5=x
X=25
The measure of a triangle is 180 degrees. In other words the sum of the angles of a triangle is 180 degrees
To solve for x set all of the expressions of angles equal to 180 and isolate x
11x - 3 + 7x + 5 + 13x - 8 = 180
31x + (- 6 + 6) = 180 + 6
31x/31 = 186 / 31
x = 6
To find the measure of each angle plug 6 into the x into each individual expression
Hope this helped!
