PLEASE HELPPP!!!! Emergency or I’ll fail the semester pls!!!!!

nasty-shy [4]

I can’t see it if you send a photo I can help

3 0

2 years ago

The number of employees for a certain company has been decreasing each year by 7%. If the company currently has 790 employees a

Vikki [24]

Answer:

The number of employees in 8 years is 442

Step-by-step explanation:

Given:

Decreasing rate = 7%

Current number of employees = 790

To Find:

The number of employees after 8 years is this same rate continues =?

Solution:

Let the number of employees after 8 years be x

The current number of employees is:

$790(1-0.07)^0=790$ ---------------------------------(1)

since the decrase rate is 7% we use 0.07

So after 8 years , eq (1) can be rewritten as

$790(1-0.07)^8= x$

$790(0.93)^8= x$

$790 \times 0.5595= x$

x= 442.005

x= 442 (approx)

6 0

2 years ago

If 30 buses can carry 1,500 people, how many people can 5 buses carry? A 200 © 500 B 250 D 750

maksim [4K]

Answer:

$\boxed {\boxed {\sf 250 \ people}}$

Step-by-step explanation:

Let's set up a proportion using the following setup.

$\frac {buses}{people}=\frac {buses}{people}$

We know 30 buses can carry 1,500 people.

$\frac {30 \ buses}{1500 \ people}=\frac {buses}{people}$

We don't know how many people 5 buses can carry, so we say 5 buses carry x people.

$\frac {30 \ buses}{1500 \ people}=\frac {5 \ buses}{x \ people}$

$\frac {30 }{1500 }=\frac {5 }{x }$

Cross multiply. Multiply the numerator of the first fraction by the second fraction's denominator. Then, multiply the first denominator by the second numerator.

$30*x=1500*5\\30x=7500$

Solve for x. It is being multiplied by 30. The inverse of multiplication is division. Divide both sides by 30.

$30x/30=7500\\x=250$

5 buses can carry 250 people.

7 0

2 years ago

Televisions are on sale for 85% of the original price of $499. How do I find out the sale price.

natulia [17]

To find your sale price you must:
$\frac{85}{100} \times 499 =$
just simply follow that operation and you're good to go

4 0

3 years ago

Read 2 more answers

While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem

Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = population proportion.

So, Null Hypothesis, $H_0$ : p = 0.013 {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, $H_A$ : p > 0.013 {means that this is an unusually high number of faulty modems}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion faulty modems= $\frac{10}{367}$ = 0.027

n = sample of modems = 367

So, the test statistics = $\frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }$

= 2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0

2 years ago