Question

ABC is a right triangle in which B is a right angle, AB= 1, AC=2 and BC= square root of 3. Cos C x sin A=

Answer 1

$cosC= sinA=\frac{BC}{AC}= \frac{ \sqrt{3} }{2} \\ \\ cosC*sinA=\left(\frac{ \sqrt{3} }{2}\right)^2= \frac{3}{4}=0.75$