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hoa [83]
3 years ago
7

Help with these two math problems?

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
3 0
Harold incorrectly completed the assignment.
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What is the effect on the graph of the function f(x) = x^2 when f(x) is changed to f(x − 6)
olya-2409 [2.1K]

Answer:

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing f(x) = x^2 and \:f\left(x\right)=\left(x-6\right)^2 is represented as being shifted 6 units to the right as compare to the function f(x) = x^2.

Step-by-step explanation:

When we Add or subtract a positive constant, let say c, to input x, it would be a horizontal shift.  

For example:

Type of change               Effect on y = f(x)

y = f(x - c)                      horizontal shift: c units to right

So

Considering the function

f(x) = x^2

The graph is shown below. The first figure is representing f(x) = x^2.

Now, considering the function

\:f\left(x\right)=\left(x-6\right)^2

According to the rule, as we have discussed above, as a positive constant 6 is added to the input, so there is a horizontal shift, 6 units to the right.

The graph of \:f\left(x-6\right)=\left(x-6\right)^2 is shown below in second figure. It is clear that the graph of  \:f\left(x-6\right)=\left(x-6\right)^2  is shifted 6 units to the right as compare to the function f(x) = x^2.

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing f(x) = x^2 and \:f\left(x\right)=\left(x-6\right)^2 is represented as being shifted 6 units to the right as compare to the function f(x) = x^2.

5 0
3 years ago
For what value of x is PQ BC pls look at picture
Jet001 [13]
Let us assume PQ || BC.
Then, by Basic Proportionality Theorem, we get,
AP/PB = AQ/QC
=> x/(x+7) = (x-3)/(x+1)
=> x (x+1) = (x+7)(x-3)
=> x^2 + x = x^2 - 3x + 7x - 21
=> x = 4x - 21
=> -4x + x = -21
=> -3x = -21
=> 3x = 21
=> x = 21/3
=> x = 7
Therefore, for PQ||BC the value of x should be 7
5 0
4 years ago
Read 2 more answers
Kristin’s three-year old sister is trying to arrange pink and red Starbursts in rows. She has 360 pink Starbursts and 150 red St
Vesnalui [34]
To find the least number of rows she can make will be found by finding the biggest way to divide these into equal groups (greatest common factor).

You can use prime factorizations of each number to find the gcf.

150 - 2 x 3 x 5 x 5
360 - 2 x 2 x 2 x 3 x 3 x 5

The common prime numbers are 2 x 3 x 5

You can make 12 (360/30) rows of pink and 5 (150/30) rows of red.
6 0
4 years ago
What's 672 divided by 32
mars1129 [50]
The answer is 21, blessup my friend stay groovy
4 0
3 years ago
Given the universal set U = {v, w, x, y, z), and subsets A = {v, w, z} and B = {x, y, z), indicate the roster
lukranit [14]

If U = {v, w, x, y, z} and A = {v, w, z}, then

A' = {x, y}

(A' is the complement of A - it's the set containing all elements of U that are not in A)

If B = {x, y, z}, then

B' = {v, w}

Their their union is

A' U B' = {v, w, x, y}

8 0
3 years ago
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