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3 years ago

12

Which bear describes the relationship between the successive terms in the sequence shown

1 answer:

Fantom [35]3 years ago

7 0

Idk what awser is just tryns get points

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julsineya [31]

You would use the equation

F+V=E+2

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3 years ago

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Assume that women's heights are normally distributed with a mean given by mu equals 63.2 in, and a standard deviation given by

JulijaS [17]

a. Your answer is correct.

b. Divide the given value of sigma by √n where n = sample size = 7. Then perform the same calculation you did for part a. The probabiilty is 0.4427.

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3 years ago

Find the equation of the line. <br><br> GIVING BRAINIEST TO WHOEVER HELPS ME AND GETS IT RIGHT!!!

Anestetic [448]

Answer:

y= -3x + 7

Step-by-step explanation:

y intercept= 7

slope= -3

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2 years ago

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The price of a 6-minute phone call is 1.80. What is the price of a 12-minute phone call?

hoa [83]

Answer:

3.60

Step-by-step explanation:

1.80 x 2

4 0

2 years ago

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What is the length of BC , rounded to the nearest tenth?

Arte-miy333 [17]

Step $1$

In the right triangle ADB

<u>Find the length of the segment AB</u>

Applying the Pythagorean Theorem

$AB^{2} =AD^{2}+BD^{2}$

we have

$AD=5\ units\\BD=12\ units$

substitute the values

$AB^{2}=5^{2}+12^{2}$

$AB^{2}=169$

$AB=13\ units$

Step $2$

In the right triangle ADB

<u>Find the cosine of the angle BAD</u>

we know that

$cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}$

Step $3$

In the right triangle ABC

<u>Find the length of the segment AC</u>

we know that

$cos(BAC)=cos (BAD)=\frac{5}{13}$

$cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{13}{AC}$

solve for AC

$AC=(13*13)/5=33.8\ units$

Step $4$

<u>Find the length of the segment DC</u>

we know that

$DC=AC-AD$

we have

$AC=33.8\ units$

$AD=5\ units$

substitute the values

$DC=33.8\ units-5\ units$

$DC=28.8\ units$

Step $5$

<u>Find the length of the segment BC</u>

In the right triangle BDC

Applying the Pythagorean Theorem

$BC^{2} =BD^{2}+DC^{2}$

we have

$BD=12\ units\\DC=28.8\ units$

substitute the values

$BC^{2}=12^{2}+28.8^{2}$

$BC^{2}=973.44$

$BC=31.2\ units$

therefore

<u>the answer is</u>

$BC=31.2\ units$

8 0

2 years ago

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