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IgorLugansk [536]
4 years ago
13

Write an inequality with x on both sides whose solution is x is greater than or equal to 2

Mathematics
2 answers:
Alja [10]4 years ago
6 0
3x - 2 > = 2x
3x - 2x > = 2
x > = 2

ryzh [129]4 years ago
4 0

Answer:

Inequality which has a solution x ≥ 2 is:

3x ≥ 2+2x

Step-by-step explanation:

We have to write an inequality with x on both sides whose solution is x is greater than or equal to 2.

x ≥ 2

Adding 2x on both sides, we get

x+2x ≥ 2+2x

3x ≥ 2+2x

Hence, inequality which has a solution x ≥ 2 is:

3x ≥ 2+2x

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Solve the equation: sin(2x)= sin x
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Answer:

Below

Step-by-step explanation:

sin(2x) = 2 ×cos(x)× sin(x)

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So we can deduce that:

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3 years ago
Examine this system of equations. Which numbers can be multiplied by each equation so that when the two equations are added toge
Karolina [17]

The first equation must be multiplied by 18 and second equation must be multiplied by 8

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

\frac{1}{4}x -\frac{1}{6}y = 5 --------- eqn 1

\frac{4}{5}x +\frac{3}{8}y = 10 -------------- eqn 2

Multiply the second equation by 8 both sides to remove the fraction in the variable y

8(\frac{4}{5}x +\frac{3}{8}y = 10)\\\\\frac{32x}{5} + 3y = 80 -------- eqn 3

Multiply the first equation by 18 both sides to obtain the coefficient -3 in the variable y

18(\frac{1}{4}x -\frac{1}{6}y = 5)\\\\\frac{18}{4}x -3y = 90 ---------- eqn 4

Add eqn 3 and eqn 4

\frac{32}{5}x +3y +\frac{18}{4}x -3y = 80+90\\\\\frac{32}{5}x+\frac{18}{4}x = 170

Thus the y-term is eliminated

Therefore, first equation must be multiplied by 18 and second equation must be multiplied by 8

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Step-by-step explanation:

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