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3 years ago

Write an inequality with x on both sides whose solution is x is greater than or equal to 2

Mathematics

2 answers:

Alja [10]3 years ago

6 0

3x - 2 > = 2x
3x - 2x > = 2
x > = 2

ryzh [129]3 years ago

4 0

Answer:

Inequality which has a solution x ≥ 2 is:

3x ≥ 2+2x

Step-by-step explanation:

We have to write an inequality with x on both sides whose solution is x is greater than or equal to 2.

x ≥ 2

Adding 2x on both sides, we get

x+2x ≥ 2+2x

3x ≥ 2+2x

Hence, inequality which has a solution x ≥ 2 is:

3x ≥ 2+2x

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Hey how would you put this in a system equation and using the Elimination method. Thank you❤

denpristay [2]

$\bf \begin{cases}
t=tacos\\
m=milk
\end{cases}~\hspace{7em}
\begin{cases}
\stackrel{1~taco}{t}+\stackrel{1~glass}{m}=\stackrel{\$}{2.10}\\[0.8em]
\stackrel{2~tacos}{2t}+\stackrel{3~glasses}{3m}=\stackrel{\$}{5.15}
\end{cases}
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\begin{array}{llll}
t+m=2.10&\stackrel{multiplied~by}{\times -3}\implies &\stackrel{notice}{-3t\stackrel{\downarrow }{-3m}=-6.3}\\[0.8em]
2t+3m=5.15&\implies &~~2t+3m=5.15\\
\cline{3-3}
&&-t+0m=-1.15
\end{array}
\\\\[-0.35em]
~\dotfill$

$\bf -t=-1.15\implies t=\cfrac{-1.15}{-1}\implies \blacktriangleright t=1.15 \blacktriangleleft
\\\\\\
\stackrel{\textit{and now substituting on the 2nd equation}}{2(1.15)+3m=5.15}\implies 2.3+3m=5.15
\\\\\\
3m=2.85\implies m=\cfrac{2.85}{3}\implies \blacktriangleright m=0.95 \blacktriangleleft$

notice, we used -3 in the multiplication to <u>eliminate</u> the m's.

6 0

3 years ago

Read 2 more answers

If John ran a 5-kilometer marathon how long was that in meters?

kolbaska11 [484]

5000 meters in 5 kilometers I'm pretty sure

3 0

3 years ago

Read 2 more answers

It is claimed that automobiles are driven on average more than 20,000 kilometers per year. To test this claim, 100 randomly sele

kow [346]

Answer:

$t=\frac{23500-20000}{\frac{3900}{\sqrt{100}}}=8.974$

$p_v =P(t_{99}>8.974)=9.43x10^{-15}$

If we compare the p value and the significance level given for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we to reject the null hypothesis, and the actual mean is significantly higher than 20000.

Step-by-step explanation:

1) Data given and notation

$\bar X=23500$ represent the sample mean

$s=3900$ represent the sample standard deviation

$n=100$ sample size

$\mu_o =2000$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mean is higher than 20000, the system of hypothesis would be:

Null hypothesis: $\mu \leq 2000$

Alternative hypothesis: $\mu > 2000$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{23500-20000}{\frac{3900}{\sqrt{100}}}=8.974$

Calculate the P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=100-1=99$