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-Dominant- [34]
2 years ago
13

20 PTSSS PLSSS HELPPPP ASP I NEED ANSWER PLUS SHOw WORK THANNKS

Mathematics
1 answer:
Gwar [14]2 years ago
6 0

Answer:

a.bh/2

b.b=A×2/h

c.12

Step-by-step explanation:

......

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Find the percentage change from<br> 40 to 60.
aliina [53]

Answer:

50%

thats the answer

5 0
3 years ago
Ellen saved $2000 and she spent 10% of it to buy a bike. Kim saved 8% more than that of Ellen's left savings. If Lisa saved 60%
enyata [817]

Answer: Lis saved $1166.4 .

Step-by-step explanation:

Given , Ellen saved $2000 and she spent 10% of it to buy a bike.

Then, Ellen's left saving = saved amount - 10% of  (saved amount)

= $2000 - 0.10 x $2000 <em>[We convert perecntage to decimal by diving it by 100]</em>

= $2000 - $200

= $1800

So, Ellen's left saving= $1800

Also, Kim saved 8% more than that of Ellen's left savings.

Kim's Saving = Ellen's left saving + 8% of (Ellen's left saving)

= $1800  + (0.08) x ($1800) <em>[We convert perecntage to decimal by diving it by 100]</em>

= $1800 +  $144

i.e. Kim's Saving= $1944

If Lisa saved 60% as much as Kim, then Lisa's saving  = 60% of (Kim's Saving)

= (0.60) x ($1944) <em>[We convert perecntage to decimal by diving it by 100]</em>

i.e. Lisa's saving = $1166.4

4 0
3 years ago
Can you answer these 3 questions for me plz
finlep [7]
A.
1hr \: 15min = 75min

c = 0.22t = 0.22 \times 75 = 16.5

cost is $16.50

B.

26.40 = 0.22 \times t

rearrange to solve for t:

t = \frac{26.40}{0.22} = 120min

C. This is the same as part B, only the rate changed

t = \frac{26.40}{0.25} = 105.6min

they ask for the greatest number of minutes, so we round down (take the floor of the value).

the answer is 105 minutes.
4 0
3 years ago
Read 2 more answers
Find the area of the surface. The part of the surface z = xy that lies within the cylinder x2 + y2 = 36.
rewona [7]

Answer:

Step-by-step explanation:

From the given information:

The domain D of integration in polar coordinates can be represented by:

D = {(r,θ)| 0 ≤ r ≤ 6, 0 ≤ θ ≤ 2π) &;

The partial derivates for z = xy can be expressed  as:

y =\dfrac{\partial z}{\partial x} , x = \dfrac{\partial z}{\partial y}

Thus, the area of the surface is as follows:

\iint_D \sqrt{(\dfrac{\partial z}{\partial x})^2+ (\dfrac{\partial z}{\partial y})^2 +1 }\ dA = \iint_D \sqrt{(y)^2+(x)^2+1 } \ dA

= \iint_D \sqrt{x^2 +y^2 +1 } \ dA

= \int^{2 \pi}_{0} \int^{6}_{0} \ r  \sqrt{r^2 +1 } \ dr \ d \theta

=2 \pi \int^{6}_{0} \ r  \sqrt{r^2 +1 } \ dr

= 2 \pi \begin {bmatrix} \dfrac{1}{3}(r^2 +1) ^{^\dfrac{3}{2}} \end {bmatrix}^6_0

= 2 \pi \times \dfrac{1}{3}  \Bigg [ (37)^{3/2} - 1 \Bigg]

= \dfrac{2 \pi}{3} \Bigg [37 \sqrt{37} -1 \Bigg ]

3 0
2 years ago
Need help on this!!!!
Alexxandr [17]

Answer:

It's the first one.

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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