Answer:
what exactly is the question to the problem ? it looks like it's already solved ? are you suppose to find something or ?
The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
Answer:
6.28meters
it is the aswer if wrong please tell me
Hey there!
#1 ⬇️
6 × 6 × 6 × 6 × 6
6 × 6 = 36
36 × 36 × 6
36 × 36 = 1,296
1296 × 6 = 7,776
Answer: 7,776 ☑️
#2 ⬇️
3 × 3 × 3 × 3
3 × 3 = 9
9 × 9 = 81
Answer: 81 ☑️
Good luck on your assignment and enjoy your day!
~LoveYourselfFirst:)
Step-by-step explanation:
the last one is the correct answer
