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Ronch [10]
3 years ago
6

What r the answers to these questions(picture above)?PLEASE HELP

Mathematics
1 answer:
kirill [66]3 years ago
6 0

Problem 3

The constant term is 290. This is the term that stays the same no matter what the value of 'a' happens to be. Contrast this with the variable term 2.50a which changes if 'a' changes (hence the name "variable" for "vary" or "change")

If Mike sold 0 accessories, then a = 0 and the expression would be

2.50*a + 290 = 2.50*0 + 290 = 290

Selling 0 accessories leads to $290. This is the amount he is guaranteed with the 2.50a portion being additional money to motivate him to sell more.

------------

Answer: Choice (3) 290, amount he is guaranteed

======================================

Problem 4

Plug y = 0 into the equation. Solve for x

9x - 14y = -3

9x - 14*0 = -3 .... replace y with 0

9x - 0 = -3

9x = -3

9x/9 = -3/9 ... divide both sides by 9

x = -3/9

x = -1/3

------------

Answer: Choice (3) which is -1/3

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wlad13 [49]

Answer:

5

Step-by-step explanation:

3 bears = 3

1 bear = 3 ÷ 3

1 bear = 1

2 glasses + 1 bear = 5

2 glasses + 1 = 5

2 glasses = 5 - 1

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1 glasses = 2

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2 Cyxus + 1 + 2 = 9

2 Cyxus = 9 - 1 - 2

              = 6

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1 glasses + 1 bear + 1 glasses + 1 Cyxus - 1 bear - 1 glasses = ?

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3 years ago
I need desperate help PLEASE!!!
koban [17]

Answer:

OPTION B

OPTION D

Step-by-step explanation:

An element in the domain should be mapped to exactly one element on the co-domain. Also, every element in the domain should be mapped to an element in the co-domain.

These two conditions are satisfied to call a relation, a function.

Two different elements in the domain can be mapped to the same element in the co-domain. But the same element in the domain cannot be mapped to two different elements in the co-domain.

A) {(3,7), (3,6), (5,4), (4,7)}

Here, the element '3' in the domain is mapped to two elements 7 and 6. So, it is not a function.

B) {(1,5), (3,5), (4, 6), (6,4)}

This is a function because all the elements in the domain have a unique image in the co-domain. So, this is a function.

C) {(2,3), (4,2), (4,6), (6,4)}

Here, the element '4' in the domain is again mapped to two different elements. Hence, it cannot be a function.

D) {(0,4), (3,2), (4,2), (6,5)}

This is again a function. Because the domain is mapped to unique elements. So, this is a function.

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