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3 years ago

What r the answers to these questions(picture above)?PLEASE HELP

Mathematics

1 answer:

kirill [66]3 years ago

6 0

Problem 3

The constant term is 290. This is the term that stays the same no matter what the value of 'a' happens to be. Contrast this with the variable term 2.50a which changes if 'a' changes (hence the name "variable" for "vary" or "change")

If Mike sold 0 accessories, then a = 0 and the expression would be

2.50*a + 290 = 2.50*0 + 290 = 290

Selling 0 accessories leads to $290. This is the amount he is guaranteed with the 2.50a portion being additional money to motivate him to sell more.

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Answer: Choice (3) 290, amount he is guaranteed

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Problem 4

Plug y = 0 into the equation. Solve for x

9x - 14y = -3

9x - 14*0 = -3 .... replace y with 0

9x - 0 = -3

9x = -3

9x/9 = -3/9 ... divide both sides by 9

x = -3/9

x = -1/3

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Answer: Choice (3) which is -1/3

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Daniel [21]

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3 years ago

Read 2 more answers

Can somebody help me with this !!!!!!!thanks

dalvyx [7]

Given:

The graph of a parabola.

To find:

The domain, range and check whether it is a function or not.

Solution:

Domain: The set of x-values or input values is known as domain.

Range: The set of y-values or output values is known as range.

A relation is a function if their exist unique outputs for each input. In other words a graph is a relation if it pass the vertical line test.

Vertical line test: Each vertical line intersect the graph at most once.

The given function is defined for all real values of x which are greater than or equal to -3. So, the domain of the given graph is:

$Domain=[-3,\infty)$

The given function values can be any real number. So, the range of the given graph is:

$Range=(-\infty,\infty)$

For x=0, we have two values of the function because the graph intercept the y-axis at two points.

Since the graph does not pass the vertical line test therefore the given graph is not a function.

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3 years ago

Cs R Solve for C t Help me solve for the indicated variable

Masteriza [31]

Answer:

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3 years ago

A six-foot-tall person is standing next to a flagpole. The person is casting a shadow 1 1/2 feet in length, while the flagpole i

lara31 [8.8K]

Answer: 20 ft

This problem can be solved by the Thales’s theorem, which states:

Two triangles are similar when they have equal angles and proportional sides

It should be noted that to apply Thales' Theorem, it is necessary to establish the two triangles are similar, that is, that they have the corresponding angles equal or that their sides are proportional to each other.

Now, if we measure the shadow of the flagpole and the shadow of the person, at the same moment, we can use the first Thales' Theorem to calculate the height of the flagpole, knowing the height of the person.

In this case we have two similar triangles (Figure attached) where $H$ is the height of the flagpole, $h=6 ft$ is the height of the person, $A=5 ft$ is the length of the shadow of the flagpole and $a=1\frac{1}{2}=1.5 ft$ is the length of the shadow of the person.