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DerKrebs [107]
2 years ago
8

1 yd² of soil containing 30% clay was mixed into 2 yd of soil containing 45% clay. What is the clay content of the mixture?​

Mathematics
1 answer:
siniylev [52]2 years ago
5 0

Answer:

105% ?

Step-by-step explanation:

I'm not entirely sure if the 1 yard 'squared' is considered in the 30% but assuming it's not ... 1yd =30% 1yd^2=60% and 2yd=45% so 60%+45%=100%

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Hey can you help me fast!!!
kotykmax [81]

Answer:

12 ft²

Step-by-step explanation:

the rectangular hole area:

l • w = A

3 • 2 = 6 ft

the triangular hole area:

(b • h) / 2 = A

(4 • 3) / 2 = 6 ft

6 ft + 6 ft = 12 ft²

7 0
3 years ago
Can you please help me with this problem.
Nimfa-mama [501]

Answer:

C

Step-by-step explanation:

Calculator did it lol

5 0
3 years ago
Points A and B are graphed points on the coordinate plane below. Which ordered pair is the coordinate location which is halfway
Setler [38]

Answer:

I cant see the image it doesnt seem to be loading but here is how to do the problem-->.

Add both the x coordinates and divide by 2 (this is the new x coordinate for the midpt)

next:

Add both y coordinates and divide by 2(this is the new y coordinate for the midpt)

Step-by-step explanation:

5 0
3 years ago
Are the ratios of 2 apples to 5 oranges and 6 apples to 14
kramer

Answer:

No

Step-by-step explanation:

Multiplying the 2 and the 5 by 3 will get you 6 and 14. 14 is not a factor of 5 making it incorrect.

3 0
3 years ago
Read 2 more answers
A Pew Internet poll asked cell phone owners about how they used their cell phones. One question asked whether or not during the
EastWind [94]

Answer:

a) \hat p=\frac{471}{1024}=0.460

The standard error is given by:

SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156

And the margin of error is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305

b) The 99% confidence interval would be given by (0.429;0.491)

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Data given and notation  

n=1024 represent the random sample taken    

X=471 represent the people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

\hat p=\frac{471}{1024}=0.460 estimated proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering    

p= population proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

Part a

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

The standard error is given by:

SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156

And the margin of error is given by:

ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305

Part b

If we replace the values obtained we got:

0.460-1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.429

0.460+1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.491

The 99% confidence interval would be given by (0.429;0.491)

8 0
3 years ago
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