X=10, the two triangles are alike except one is double the size of the other. hope this helps
Answer:
- The area of rhombus JKLM is 48 units²
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<h3>Given </h3>
- Rhombus JKLM,
- Vertices at J(-2, -4), K(2, 2), L(6, -4), M(2, -10).
<h3>To find </h3>
<h3>Solution</h3>
We know that diagonals of rhombus are perpendicular to each other.
Hence its area is half the product of diagonals.
The diagonals are JL and KM and one of them is vertical and the other one horizontal since x- or y-coordinates are equal in pairs.
Let's find the length of diagonals, using the difference of coordinates:
- JL = 6 - (-2) = 8 units,
- KM = 2 - (-10) = 12 units.
Now find the area:
- A = JL*KM /2 = 8*12 / 2 = 48 units²
Answer:
Step-by-step explanation:
in third quadrant sin is negative.
sin² θ+cos² θ=1
sin²θ+(-16/20)²=1
sin²θ+(-4/5)²=1
sinθ=±√(1-16/25)
=±√((25-16)/25)
=±√(9/25)
=±3/5
so
sin θ=-3/5
To solve these, basically find out how many numbers satisfy your requirment, then divide that number by 10. Simplify your fraction and you have your probability.
probability of getting a 10: 1/10
probability of getting a 5: 1/10
probability of not getting 10: 9/10
probability of getting an odd number: 5/10
probability of getting a number less than 4: 3/10
probability of getting a number greater than 7: 3/10
Hope this helps, and muchas luck on your math!