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frez [133]
4 years ago
13

Please help asap :)

Mathematics
1 answer:
Bad White [126]4 years ago
4 0

Answer:

The measure of ∠D = (Q) = 28.81

Step-by-step explanation:

Tan(Q) = perpendicular/ base

In this case perpendicular  is BC and base is DC

BC =25   DC = 45

Tan(Q) = BC/DC

Tan(Q) = 25/ 45

Tan(Q) = 5/ 9

(Q) = tan^ -1 (0.55)

(Q) = 28.81

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kompoz [17]
Your answer is correct
6 0
3 years ago
Help pls<br><br>Find x<br>a(21)<br>b(27)<br>c(9)<br>d(18)​
tino4ka555 [31]

9514 1404 393

Answer:

  a.  21

Step-by-step explanation:

The external part of the hypotenuse of the right triangle is shown. The full length of the hypotenuse is 9+20 = 29. The Pythagorean theorem can be used to find x.

  x^2 +20^2 = 29^2

  x^2 = 841 -400

  x = √441

  x = 21

__

<em>Alternate solution</em>

The diameter of the circle is 2·20 = 40 units, so the product of distances from the external vertex to the opposite sides of the circle along the secant is (9)(40+9). The product of the distances along the tangent is x·x. These two products are equal, so ...

  x^2 = 9(49)

  x = (√9)(√49) = 3·7

  x = 21

3 0
3 years ago
20. Q(-1, 4), R(-1, -9), S(11, -2), T(11, 6)
s2008m [1.1K]

Answer:

Parallel

Step-by-step explanation:

QR and ST both parallel to y axis.

3 0
3 years ago
Given sinx=3/5 and x is in quadrant 2, what is the value of tan(x/2)
xxMikexx [17]
X is in the second quadrant means that x/2 is in the first quadrant.


Consider the right triangle drawn in the figure. Let tan(x/2)=a.

Then, let the length of the opposite side to x/2 be a, the adjacent side be 1 and the hypotenuse be square root of a squared +1, as shown in the figure.

sin(x/2)=|opp side|/ |hypotenuse| =  \frac{a}{ \sqrt{ a^{2}+1 } }

cos (x/2) = |adj side|/ |hypotenuse| =  \frac{1}{ \sqrt{ a^{2}+1 } }


from the famous identity: sin(2a)=2sin(a)cos(a), we have:

2sin(x/2)cos (x/2)=sin(x)

thus

2* \frac{a}{ \sqrt{ a^{2}+1 } }*\frac{1}{ \sqrt{ a^{2}+1 } }= \frac{3}{5}

2* \frac{a}{  a^{2}+1 }= \frac{3}{5}

10a=3 a^{2} +3

3 a^{2}-10a +3=0

(3a-1)(a-3)=0

thus a=1/3 or a=3


thus tan(x/2)=1/3 or tan(x/2)=3


Answer: {1/3, 3}

3 0
3 years ago
Read 2 more answers
A function of the form f(x) = mx + b, where m and b are real numbers, is called a _____
jasenka [17]

Answer:

A function of the form f(x) = mx + b, where 'm' and 'b' are real numbers, is called a <u>linear function.</u>

Step-by-step explanation:

A linear function is one in which the f(x) value of the function varies linearly with 'x'. When we plot a linear function on a graph, the resulting curve is always a straight line with the slope of the line being constant.

A linear function is of the form:

f(x)=mx+b, where, 'm' and 'b' are real numbers.

The degree or the highest exponent of 'x' in a linear function is always equal to 1.

Therefore, a function of the form f(x) = mx + b, where 'm' and 'b' are real numbers, is called a <u>linear function.</u>

4 0
3 years ago
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