Question

I need help on this problem...

Answer 1

Option C:

x = 0

Solution:

Given equation : $\frac{1}{2}(x-14)+11=\frac{1}{2} x-(x-4)$

To find the value of x from the given equation.

$\frac{1}{2}(x-14)+11=\frac{1}{2} x-(x-4)$

$\Rightarrow\frac{1}{2}x-7+11=\frac{1}{2} x-x+4$

$\Rightarrow\frac{1}{2} x+4=-\frac{1}{2} x+4$

Subtract 4 from both sides of the equation.

$\Rightarrow\frac{1}{2} x+4-4=-\frac{1}{2} x+4-4$

$\Rightarrow\frac{1}{2} x=-\frac{1}{2} x$

Arrange like terms in one side of the equation.

Negative term changed to positive term when it goes to left side of the equation.

$\Rightarrow\frac{1}{2} x+\frac{1}{2} x=0$

$\Rightarrow\frac{1+1}{2} x=0$

$\Rightarrow\frac{2}{2} x=0$

$\Rightarrow x=0$

Option C is the correct answer.

The value of x is 0.