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slava [35]
3 years ago
7

The roots of a quadratic function are x = -3 and x = 2/3. Which of the following would be the constant term of the equation in s

tandard form?
A. -2
B. 6
C. 2
D. -6
Mathematics
1 answer:
Alla [95]3 years ago
7 0

Answer:

-2

Step-by-step explanation:

Since the roots are known and the function is a quadratic function, we can write down the function:

y = (x+3)(x-2/3) since when the roots are plugged in, the function gives 0.

Standard form means that the function has to be expanded:

y = (x+3)(x-2/3) = x^{2}+3x - 2x/3 - 3*2/3

y = x^{2}+ 7x/3 - 2

The constant term is -2.

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Standard error = \frac{\sigma}{\sqrt{n} } where σ is the standard deviation.

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Standard error = \frac{\sigma}{\sqrt{n} }= \frac{\sqrt{np(1-p)} }{\sqrt{n} } =\sqrt{\frac{np(1-p)}{n} } =\sqrt{p(1-p)}=\sqrt{0.24(1-0.24)}  =0.427

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If f(x)=x^2+3x, what is the average rate of change of f(x) over the interval [-2,3]?
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