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Setler79 [48]
3 years ago
12

7x+8(x+1/4)=3(6x-9)-8 need a solution for this problem

Mathematics
1 answer:
valentina_108 [34]3 years ago
5 0
7x+8(x+1/4) = 3(6x-9)-8
7x+8x+2      = 18x - 27 -24
15x + 2        =  18x - 51
       +51                        + 51
15x + 53      = 18x
-15x             = -15x
          53       = 3x
          17.66  = x
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Answer:

y=-3x+5

Explanation:

Given a line L such that:

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,

• L is perpendicular to the line with equation y=(1/3)x+1.

We want to find the equation of the line in the slope-intercept form.

The slope-intercept form of the equation of a straight line is given as:

\begin{equation} y=mx+b\text{ where }\begin{cases}m={slope} \\ b={y-intercept}\end{cases} \end{equation}

Comparing the given line with the form above:

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Next, we find the slope of the perpendicular line L.

• Two lines are perpendicular if the product of their slopes is -1.

Let the slope of L = m1.

Since L and y=(1/3)x+1 are perpendicular, therefore:

\begin{gathered} m_1\times\frac{1}{3}=-1 \\ \implies Slope\text{ of line L}=-3 \end{gathered}

The y-intercept of L is at (0,5), therefore:

y-intercept,b=5

Substitute the slope, m=-3, and y-intercept, b=5 into the slope-intercept form.

\begin{gathered} y=mx+b \\ y=-3x+5 \end{gathered}

The equation of line L is:

y=-3x+5

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