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UkoKoshka [18]
3 years ago
11

a seamstress needs to cut 15inch pieces of ribbon from a rool of ribbon thats is 9 feet in lenght.What is the greatest number of

15inch pieces the seamstress can cut from 5 of rolls of ribbon?
Mathematics
1 answer:
monitta3 years ago
3 0
There are 108 inches in 9 feet but there are 5 so 108×5= 540 so to get your answer you need to divide that by 15 which equals 36. so you can make 36 pieces
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Need help solving this question please.
jok3333 [9.3K]

Answer: b) they loaded 112356 lbs of cargo

Step-by-step explanation:

When a boat or an object floats in water, the volume of water that it displaces is equivalent to its weight.

When moving into the port, the cargo boat displaced 2200 ft³ of water. Since the density of water is 62.42 lb/ft³ and mass = density × volume, then the mass of the cargo boat on entering the port is

2200 × 62.42 = 137324 lbs

On leaving the port, it displaces 4000 ft³ of water. The mass of the cargo boat on leaving the port is

4000 × 62.42 = 249680 lbs

The difference in both masses is

249680 - 137324 = 112356 lbs

Therefore, they loaded 112356 lbs of cargo

4 0
3 years ago
M and m<br> Please find quick
Lady_Fox [76]

Answer:

wELL YOU WANT TO GRAB SOME M AND MS AND EAT THEM

Step-by-step explanation:

4 0
3 years ago
Ill give brainliest for the answer and no guessing
Vsevolod [243]

Answer:

12350%

Step-by-step explanation:

. 76 - 34 = 42

. 42 divided by 34 = 1.23529411765

. 1.23529411765 multiplied by 100 = 123.529411765

. 123.529411765 ≈ 123.5 * 100 = 12350%

7 0
2 years ago
The Difference BETWEEN the CI and SI on a Certain sum of money for 2 years at 15% per annum is RS.180.Find the sum
klio [65]

Step-by-step explanation:

when the difference between CI and SI given then the sum =

difference (100/r)^2

given difference is Rs . 180

Rate of interest is 15%

sum = 180× (100/15)^2

180×10000/225

= 8000

8 0
3 years ago
Mike and Ike are twins. Mike’s age is one more than twice a certain number. Ike’s age is 10 less than triple that same number. F
Misha Larkins [42]
Mike age is 3 less then twice the age of his brother nuke.
M = Mike's age now
N = Nuke's age now
M = 2N - 3

Ten years ago, four times nuke's age was one more mike's age.
M-10 = Mike's age 10 years ago
N-10 = Muke's age 10 years ago
4(N - 10) = 1 + M -10

what are their present ages

find M and N

substitute M = 2N - 3 into 4(N - 10) = 1 + M -10:

4(N - 10) = 1 + [2N - 3] - 10
4N - 40 = 2N - 12
2N = 28
N = 14

M = 2(14) - 3 = 28 - 3 = 25

Mike is 25 and Nuke is 14.

check:
4(14 - 10) = 4(4) = 16 = 26 -10 = 1 + 25 - 10
4 0
2 years ago
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