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Bad White [126]
3 years ago
15

How do I find this answer and what is the answer?

Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
8 0
QR = PR - PQ

QR = 13y + 25 - (8y + 5)
QR = 13y + 25 - 8y - 5
QR = 5y + 20 <==
kramer3 years ago
6 0
The length of QR is the length of PR minus the length of PQ. So write out the formula:
(13y + 25) - (8y + 5) 

Expand
13y + 25 -8y - 5

Combine
5y + 20

So the length of QR is 5y + 20

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Tanya [424]
Answer: A. 4.
Explanation: solving graphically
6 0
1 year ago
Surface integrals using an explicit description. Evaluate the surface integral \iint_{S}^{}f(x,y,z)dS using an explicit represen
Jobisdone [24]

Parameterize S by the vector function

\vec r(x,y)=x\,\vec\imath+y\,\vec\jmath+f(x,y)\,\vec k

so that the normal vector to S is given by

\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=\left(\vec\imath+\dfrac{\partial f}{\partial x}\,\vec k\right)\times\left(\vec\jmath+\dfrac{\partial f}{\partial y}\,\vec k\right)=-\dfrac{\partial f}{\partial x}\vec\imath-\dfrac{\partial f}{\partial y}\vec\jmath+\vec k

with magnitude

\left\|\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}\right\|=\sqrt{\left(\dfrac{\partial f}{\partial x}\right)^2+\left(\dfrac{\partial f}{\partial y}\right)^2+1}

In this case, the normal vector is

\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=-\dfrac{\partial(8-x-2y)}{\partial x}\,\vec\imath-\dfrac{\partial(8-x-2y)}{\partial y}\,\vec\jmath+\vec k=\vec\imath+2\,\vec\jmath+\vec k

with magnitude \sqrt{1^2+2^2+1^2}=\sqrt6. The integral of f(x,y,z)=e^z over S is then

\displaystyle\iint_Se^z\,\mathrm d\Sigma=\sqrt6\iint_Te^{8-x-2y}\,\mathrm dy\,\mathrm dx

where T is the region in the x,y plane over which S is defined. In this case, it's the triangle in the plane z=0 which we can capture with 0\le x\le8 and 0\le y\le\frac{8-x}2, so that we have

\displaystyle\sqrt6\iint_Te^{8-x-2y}\,\mathrm dx\,\mathrm dy=\sqrt6\int_0^8\int_0^{(8-x)/2}e^{8-x-2y}\,\mathrm dy\,\mathrm dx=\boxed{\sqrt{\frac32}(e^8-9)}

5 0
2 years ago
Stuck on this problem, please help
hoa [83]
The answer is :23
B:34
C:56
7 0
2 years ago
Read 2 more answers
A 4-kilogram bag of birdseed costs $12.69. What is the unit price, rounded to the
igomit [66]

Answer:

$3.17

Step-by-step explanation:

Take the $12.69 and divide it by the 4 kilograms and you get 3.17. (This is rounded)

3 0
3 years ago
An isosceles triangle has a base 9.2 units long. If the congruent side lengths have measures to the first decimal place, what is
Nadusha1986 [10]

Question:

An isosceles triangle has a base of 9.6 units long. If the congruent side lengths have measures to the first decimal place, what is the possible length of the sides? 9.7, 4.9, or 4.7

Answer:

4.9 is the shortest possible length of the sides.

Step-by-step explanation:

Given:

The base of the triangle base  =   9.2 units

To Find:

The shortest possible length of the sides = ?

Solution:

The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side.

So According to the theorem

x+x > 9.6

2x > 9.6

x > \frac{9.6}{2}

x > 4.8

In the given option 4.9 is the shortest length greater than 4.8 that can be possible.

3 0
3 years ago
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