The quadratic equation cannonball’s path if it was launched with the same velocity, but from the ground instead would be given by:

<h3>What is the quadratic equation for the height of a projectile?</h3>
Considering the gravity, it is modeled by:

In which:
is the initial velocity.
is the initial height.
For this problem, we want:
- The same initial velocity, hence
.
- Launched from the ground, hence
.
Then, the equation is:

More can be learned about quadratic equations at brainly.com/question/24737967
Answer:
tubirau dau dau thubirau dau dau
Step-by-step explanation: balakulik utag upa
tu e gay mano?
Step-by-step explanation:
Check if f(−x)=f(x) f ( - x ) = f ( x ) . Since x2−2x x 2 - 2 x ≠ ≠ x2+2x x 2 + 2 x , the function is not even. A function is odd if f(−x)=−f(x) f ( - x ) = - f ( x ) .
Answer:
Step-by-step explanation:
Perimeter is
P = 2L + 2W. We are given the perimeter as 180 feet, so
180 = 2L + 2W. Solve this for either L or W. I chose W, no reason...
180 - 2L = 2W so
90 - L = W Hold that thought. We'll come back to it in a minute.
Area is
A = LW. We are given the area as 1800 square feet, so
1800 = LW. Sub in 90 - L for W:
1800 = L(90 - L). Distribute to get a quadratic:

Get everything on one side and solve for the length by factoring:

Factor this however you like to factor quadratics, to get the length of
L = 30 and L = 60. First off, the length is longer than the width in general, so if we want to solve for the width, plug in 60 as L in the equation in bold print:
90 - 60 = W and
30 = W
So L = 60 and W = 30
Answer:
225
Step-by-step explanation:
(17+8)*(14-3)=25*9=225