We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so
</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>
</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>
remember that
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
Answer:
A.) (x + 2) and (2x - 1)
Step-by-step explanation:
So from the video i just watch this is how its done
3 (2x^2 + 3x - 2) = 0
4 and -1 gives you 3 and you divide them by a which is 2
4/2 (2/1) and -1/2 then you write them from the bottom to top
(x + 2) and (2x - 1)
Answer:
B.) 20 (x + 5) (x - 5) = 0
Step-by-step explanation:
20 (x^2 - 25) = 0
20 (x + 5) (x - 5) = 0
EZ
Hello from MrBillDoesMath!
Answer:
68
Discussion:
85% of 80 =
(85/100) * 80 = => as 85* 8 = (80 +5) * 8 = 640 + 40 = 680
6800/100 =
68
Thank you,
MrB