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sashaice [31]
2 years ago
12

|x|+|x+1|+|x+2|+|x+3|+...+|x+2021=2021x​

Mathematics
1 answer:
BlackZzzverrR [31]2 years ago
3 0

Answer:

jo pahle wale X hai na na X + x plus 1 unhen Yad Karke answer 1 aaega FIR X + 2 =_= + 3 X + 3 yah answer Aaya 1 or 2 X + ka ok

Step-by-step explanation:

FIR hai x+ x and ++ 2021 x

2021x

FIR + Kannan donon ko x

ans

x - 3 X

x - 4042

yah answer aayega ine donon ka the solve this question ok friend

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What is t+8=15 write how u found out show ur work thanx plz hellppppp
Pachacha [2.7K]

The answer is the number that 't' must be in order for the equation
to be a true statement.

Here's how to find it:

Write                                             t + 8 = 15

Then subtract 8 from each side:  <em>  t      =  7</em>


8 0
3 years ago
Read 2 more answers
What is the output of the expression 14/3<br>​
hram777 [196]

I did

14/3=4 2/3

so the final answer is 4 and 2/3

8 0
3 years ago
Please I need to know if its true or false please lmk!!!​
Papessa [141]

Answer:

False

Step-by-step explanation:

<u>According to the complex conjugate root theorem:</u>

if a complex number is a root of a polynomial, its conjugate is also the root of the polynomial

We are given all the roots of the polynomial and there is only one complex root

Since according to the complex conjugate root theorem, there can be either none or at least 2 complex roots of a polynomial

We can say that this set of roots of a polynomial is incorrect

7 0
2 years ago
Read 2 more answers
16 POINTS
Marta_Voda [28]
Solve the following system using elimination:
{7 x + 2 y = -19 | (equation 1)
{2 y - x = 21 | (equation 2)

Add 1/7 × (equation 1) to equation 2:
{7 x + 2 y = -19 | (equation 1)
{0 x+(16 y)/7 = 128/7 | (equation 2)

Multiply equation 2 by 7/16:
{7 x + 2 y = -19 | (equation 1)
{0 x+y = 8 | (equation 2)

Subtract 2 × (equation 2) from equation 1:
{7 x+0 y = -35 | (equation 1)
{0 x+y = 8 | (equation 2)

Divide equation 1 by 7:
{x+0 y = -5 | (equation 1)
{0 x+y = 8 | (equation 2)

Collect results:
Answer: {x = -5, y = 8
8 0
3 years ago
Find the directional derivative of f(x,y,z)=2z2x+y3f(x,y,z)=2z2x+y3 at the point (−1,4,3)(−1,4,3) in the direction of the vector
Feliz [49]

f(x,y,z)=2z^2x+y^3

f has gradient

\nabla f(x,y,z)=2z^2\,\vec\imath+3y^2\,\vec\jmath+4xz\,\vec k

which at the point (-1, 4, 3) has a value of

\nabla f(-1,4,3)=18\,\vec\imath+48\,\vec\jmath-12\,\vec k

I'm not sure what the given direction vector is supposed to be, but my best guess is that it's intended to say \vec u=15\,\vec\imath+25\,\vec\jmath, in which case we have

\|\vec u\|=\sqrt{15^2+25^2}=5\sqrt{34}

Then the derivative of f at (-1, 4, 3) in the direction of \vec u is

D_{\vec u}f(-1,4,3)=\nabla f(-1,4,3)\cdot\dfrac{\vec u}{\|\vec u\|}=\boxed{\dfrac{294}{\sqrt{34}}}

4 0
3 years ago
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