X^2 + y^2 = 25
2x + y = -5.....y = -2x - 5
x^2 + (-2x - 5)^2 = 25
x^2 + (-2x - 5)(-2x - 5) = 25
x^2 + (4x^2 + 20x + 25) = 25
5x^2 + 20x + 25 = 25
5x^2 + 20x = 0
5x(x + 4) = 0
5x = 0 2(0) + y = -5
x = 0 y = -5
x + 4 = 0 2(-4) + y = -5
x = -4 -8 + y = -5
y = 3
solutions are : x = 0, y = -5.....and x = -4, y = 3
Answer:
46
Step-by-step explanation:
Since B is the midpoint of AC, the segments AB and BC must have equal length. This means that x + 13 = 2x + 3. Solving this, we see that x = 10. By substituting 10 for x, we see that the length of AB is 23, so the length of AC is 2*23, which is 46.
What textbook is it the texas math textbook or wat
Answer:
7, 4ft
Step-by-step explanation:
Given data
area = 108 square feet
length = (x-1)
width = (x-4)
Area=L*W
open bracket
a= 1
b=-5
c=-104
Applying the quadratic formula
x=-13
or
x=8
since x cannot be negative
x= 8
length = (x-1)= 8-1= 7ft
width = (x-4)= 8-4= 4ft
You do 7 times 2 in parentheses and then minus that by 6-4 in parentheses so it will look like this , (7times2) - (6-4) = 12
