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makvit [3.9K]
3 years ago
13

Which statement is correct ?

Mathematics
1 answer:
Fiesta28 [93]3 years ago
8 0

Answer:yes , because a c b are located equally

Step-by-step explanation:

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Tina is growing sunflowers in her garden. The flowers are currently 6 inches tall each week x, they will double in size . Which
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For this case we have an equation of the form:
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 Answer:
 
An equation that best represent how tall the sunflower will b in x weeks is:
 
y = 6 (2) ^ x
6 0
3 years ago
Find the remainder when x⁵+x³+x is divided by x-3. State whether the binomial is a factor of the polynomial
mestny [16]
It is not a polynomial
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3 years ago
Which of the following points is collinear with (1, 1), and (2, 2)? (4, 1) (3, 2) (5, 6) (3, 3)
aleksandrvk [35]
<span>Points (1, 1), and (2, 2) are on a line which has a slope of 1

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The only point that lies on this line is (3,3).
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5 0
4 years ago
A sports teacher had 1025 sweets. After distributing these equally amongst all the participants in a sports meet, he had just 1
Cerrena [4.2K]

Step-by-step explanation:

Since it remains only 1 sweet, we can subtract it from the total and get the amount of sweets distributed (=1024).

As all the sweets are distributed equally, we must divide the number of distributed sweets by all its dividers (excluding 1024 and 1, we'll see later why):

1) 512 => 2 partecipants

2) 256 => 4 partecipants

3) 128 => 8 partecipants

4) 64 => 16 partecipants

5) 32 => 32 partecipants

6) 16 => 64 partecipants

7) 8 => 128 partecipants

9) 4 => 256 partecipants

10) 2 => 512 partecipants

The number on the left represents the number of sweets given to the partecipants, and on the right we have the number of the partecipants. Note that all the numbers on the left are dividers of 1024.

Why excluding 1 and 1024? Because the problem tells us that there remains 1 sweet. If there was 1 sweet for every partecipant, the number of partecipants would be 1025, but that's not possible as there remains 1 sweet. If it was 1024, it wouldn't work as well because the sweets are 1025 and if 1 is not distributed it goes again against the problem that says all sweets are equally distributed.

5 0
3 years ago
Select all of the following ordered pairs that are in the solution set of the inequality shown.
Ilya [14]

Answer:

points on the boundary line: (0, 10), (20, 0)

solution points not on the boundary line: (100, 100)

Step-by-step explanation:

We cannot tell from the posted picture whether the boundary line is solid or dashed, so the answer above is split into two parts. If the boundary line is solid (x+2y≥20), all three listed points are in the solution set. If the boundary line is dashed (x+2y>20), only (100, 100) is in the solution set

5 0
3 years ago
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