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Stels [109]
3 years ago
6

Justin is redoing his bathroom floor with tiles measuring 6in. by 14 in. The floor has an are of 8,500 in. What is the least num

ber of tiles he will need?
Mathematics
1 answer:
valina [46]3 years ago
5 0

area of tile = 6 *14 = 84 square inches

number of tiles = 8500/84 = 101.19

102 tiles are needed

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The area of a rectangle is 45 cm2. Two squares are constructed such that two adjacent sides of the rectangle are each also the s
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Answer:

The length of sides of one square is 5cm  and length of sides of another square is 9cm

Step-by-step explanation:

Let the length of rectangle be x and width of rectangle be y.

We have given,

Area of rectangle = 45 cm²

i.e. Area of rectangle = x·y = 45  or xy = 45   ---------(1)

Next, two squares are constructed from two adjacent sides of rectangle.

i.e Side length of one square will be x and side length of another square will be y.

Area of one square = x²

And area of another square = y²

According to problem,

Sum of area of two squares is 106 cm²

∴ x²+y² = 106   ---------------(2)

From equation (1) and (2) , we can find x and y.

xy = 45  or x = \frac{45}{y}  , Plug this in equation (2).

We get,

x² + y² = 106

or (\frac{45}{y} )^{2} + y^{2} =106

or \frac{45^{2} +y^{4} }{y^{2} } =106

or 45^{2} + y^{4} = 106y^{2}

On solving this equation we get ,

y²=81 or 25

or y = 9 or 5

for y =9 , x= \frac{45}{9} =5

or for y = 5 , x = \frac{45}{5} =9

Hence the length of sides of one square is 5cm  and length of sides of another square is 9cm

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{\qquad\qquad\huge\underline{{\sf Answer}}}

Let's solve ~

By using distance formula :

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