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IgorC [24]
2 years ago
5

Is 7/9 greater than or less than 0.6

Mathematics
1 answer:
LekaFEV [45]2 years ago
6 0
7/9 is greater because if you divide the fraction you will get 0.77777777...
(Which will go on forever)

compare:  
        (< or >)  
0.7      ?      0.6

Well, by looking at both of them, you can easily tell that 0.7 is greater and 0.7=7/9, therefore, 7/9 is greater 

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Determine if the ordered pair (6, 4) is a solution to the inequality
Ugo [173]

Answer:

\Large \boxed{\mathrm{Option \ D}}

Step-by-step explanation:

(6, 4)

x = 6 and y = 4

y > -1/2x + 7

Plug in the values to check if it is true.

4 > -1/2(6) + 7

4 > -3 + 7

4 > 4

This statement is false.

(6, 4) lies on the line.

8 0
3 years ago
What does 876+736 equal
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<h2>1,612 FOLLOW ME FOR CLEARING YOUR NEXT DOUBT </h2>
5 0
2 years ago
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The train ride at the zoo covers a distance of 2 1/2 miles in 1/3 of an hour. How many miles per hour does the train go? How far
Gala2k [10]
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6 0
3 years ago
A blank is a unit rate with a denominator of 1 unit. What is the the blank?
Bumek [7]

A unit rate is a ratio that has a denominator of 1. A unit rate is also called a unit ratio. (They mean the same thing.)

\frac{5}{4} and 3:8 and 40\mbox{ to }10 are ratios, but they are not unit ratios.

\frac{1.25}{1} and 0.375:1 and 4\mbox{ to }1 are unit ratios.

Any ratio can be converted into a unit ratio by dividing the numerator and the denominator by the denominator.


4 0
3 years ago
Prove that : sinA/1+cosA + 1+cosA/sinA=2cosecA​
tekilochka [14]

Step-by-step explanation:

\frac{sinA}{1+cosA} +\frac{1+cos}{sinA} =2cosec\\\\\\\frac{sin^{2}A+(1+cos)^{2}  }{sinA(1+cosA)} \\\\

\frac{sin^{2}A+1+cos^{2}+2cos}{sinA(1+cosA)} \\\\ and we have sin^{2}+cos^{2} =1

so \frac{1+1+2cosA  }{sinA(1+cosA)} \\\\

\frac{2+2cosA  }{sinA(1+cosA)} \\\\

\frac{2(1+cosA)}{sinA(1+cosA)} \\\\

\frac{2}{sinA} we have \frac{1}{sin}=cosec\\

<em>Finally </em>2cosecA<em />

<em>I really hope this helps coz it took much time </em>

3 0
2 years ago
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