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2 years ago

Is 7/9 greater than or less than 0.6

1 answer:

6 0

7/9 is greater because if you divide the fraction you will get 0.77777777...
(Which will go on forever)

compare:
(< or >)
0.7 ? 0.6

Well, by looking at both of them, you can easily tell that 0.7 is greater and 0.7=7/9, therefore, 7/9 is greater

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What is the total weight for each group of weight of clay lumps

Verizon [17]

Hey, me again! So, I'll be giving you the totals for EACH group.

For the first group, multiply 1/8 by 3 to get the answer;
3/8 lbs

Do the same for this group (and all of the others) so that the answers are:
Group 2 - 3/4lbs
Group 3 - 2/2 = 1lb
Group 4 - 5/8lb
Group 5 - 7/8

5 0

3 years ago

If f(x) = 3x - 1 and g(x) = x + 2, find (f+g)(x)

Ivan

Answer:

(f - g)(x) = f(x) - g(g) = (3x + 1) - (x2 - 6) = -x^2 + 3x + 7

Step-by-step explanation:

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2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%20%5Csqrt%7Bx%20%5Csqrt%7Bx%20%5Csqrt%7Bx....%7D%20%7D%20%7D%20%7D%20%20%3D%20%

andrey2020 [161]

First observe that if $a+b>0$ ,

$(a + b)^2 = a^2 + 2ab + b^2 \\\\ \implies a + b = \sqrt{a^2 + 2ab + b^2} = \sqrt{a^2 + ab + b(a + b)} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b(a+b)}}} \\\\ \implies a + b = \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{a^2 + ab + b \sqrt{\cdots}}}}$

Let $a=0$ and $b=x$ . It follows that

$a+b = x = \sqrt{x \sqrt{x \sqrt{x \sqrt{\cdots}}}}$

Now let $b=1$ , so $a^2+a=4x$ . Solving for $a$ ,

$a^2 + a - 4x = 0 \implies a = \dfrac{-1 + \sqrt{1+16x}}2$

which means

$a+b = \dfrac{1 + \sqrt{1+16x}}2 = \sqrt{4x + \sqrt{4x + \sqrt{4x + \sqrt{\cdots}}}}$

Now solve for $x$ .

$x = \dfrac{1 + \sqrt{1 + 16x}}2 \\\\ 2x = 1 + \sqrt{1 + 16x} \\\\ 2x - 1 = \sqrt{1 + 16x} \\\\ (2x-1)^2 = \left(\sqrt{1 + 16x}\right)^2$

(note that we assume $2x-1\ge0$ )

$4x^2 - 4x + 1 = 1 + 16x \\\\ 4x^2 - 20x = 0 \\\\ 4x (x - 5) = 0 \\\\ 4x = 0 \text{ or } x - 5 = 0 \\\\ \implies x = 0 \text{ or } \boxed{x = 5}$

(we omit $x=0$ since $2\cdot0-1=-1\ge0$ is not true)

3 0

1 year ago

A large research hospital is considering a new computer-based training course for lab safety. The total cost of the hospital's c

Katarina [22]

I need that money to but new nikes

8 0

3 years ago

Read 2 more answers

Please help I really need help please

fomenos

Answer:

Step-by-step explanation:

The side lengths must satisfy the Pythagorean Theorem to be a right triangle. The formula is $a^2 + b^2 = c^2$ where a is the smallest side, b is the medium side, and c is the largest side. Test each set of numbers.

$a = 6, b = 8, c= 10\\6^2 + 8^2 = 10^2\\36 + 64 = 100\\100 = 100$

This satisfies the theorem. Since this is a multiple choice question, only one solution is possible. A is the solution.

6 0

3 years ago