Answer:
The probability that a randomly selected call time will be less than 30 seconds is 0.7443.
Step-by-step explanation:
We are given that the caller times at a customer service center has an exponential distribution with an average of 22 seconds.
Let X = caller times at a customer service center
The probability distribution (pdf) of the exponential distribution is given by;

Here,
= exponential parameter
Now, the mean of the exponential distribution is given by;
Mean =
So,
⇒
SO, X ~ Exp(
)
To find the given probability we will use cumulative distribution function (cdf) of the exponential distribution, i.e;
; x > 0
Now, the probability that a randomly selected call time will be less than 30 seconds is given by = P(X < 30 seconds)
P(X < 30) =
= 1 - 0.2557
= 0.7443
They ate 2/3 together. And, they have 1/3 left!
When simplified all of them equal 3/1. They are asking you to just chose 4 of them. Hope that helps!
Answer:
mLNM=63
Step-by-step explanation:
triangle JKL is isocelese so mKJL and KLJ are the same
180-72=108
108/2=54
so both mKLJ and mMLN are equal
and since triangle LMN is an isoceles then mLNM and mLMN are equal to each other
so 180-54=126
126/2=63
mLNM=63
If there are 4 people and you want the time for EACH person then you would do 62.59
Which = 15.6475