Answer:
31.9secs
6,183.3m
Step-by-step explanation:
Given the equation that models the height expressed as;
h(t ) = -4.9t²+313t+269
At the the max g=height, the velocity is zero
dh/dt = 0
dh/dt = -9,8t+313
0 = -9.8t + 313
9.8t = 313
t = 313/9.8
t = 31.94secs
Hence it takes the rocket 31.9secs to reach the max height
Get the max height
Recall that h(t ) = -4.9t²+313t+269
h(31.9) = -4.9(31.9)²+313(31.9)+269
h(31.9) = -4,070.44+9,984.7+269
h(31.9) = 6,183.3m
Hence the maximum height reached is 6,183.3m
2/5 + 2/4 = 8/20 + 10/20 = 18/20 = 9/10
Answer:
n = 14
Step-by-step explanation:
7n +9 = -1+6(n+4)
Distribute
7n+9 = -1 +6n+24
Combine like terms
7n +9 = 6n +23
Subtract 6n from each side
7n -6n+9 = 6n-6n +23
n+9 = 23
Subtract 9 from each side
n+9-9=23-9
n = 14