How do I solve/put this in point slope form? (-3,-2) (5,3)
1 answer:
Answer:
Considering you know two points, you will need to find the slope.
To find the slope you will use the equation added.
3 - (-2) = 3 + 2 = 5
5 - (-3) = 5 + 3 = 8
m = 5/8
Next you will use the point slope form equation.
Adding first point:
y - (-2) = m( x - (-3) )
Adding second point:
3 - (-2) = m( 5 - (-3) )
Adding slope:
3 + 2 = 5/8( 5+3 )
Solving sides / Check:
3 + 2 = 5/8( 8 )
5 = 5
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All the work is shown and simplified, if anything is missed LMK!
↝ Form into where a > 0 (Optional)
↝ Multiply -1 for both sides.
↝ Then proceed with the Quadratic Formula.
x = [-b ± (√b²-4ac)]/2a ↝ Quadratic Formula
↝ As you can see that inside the square root, the numbers cannot be negative. Therefore, the solutions are imaginary.
↝ Solution with Real Numbers System ↝ There are no real solutions.
↝ Solution with Complex Number System ↝
Therefore, the answer for Complex Number System is (5±√7i)/2