Length of the perpendicular ( opposite ) = 6 cm.
Length of the base ( adjacent ) = 8 cm.
The smallest angle of the triangle.
✅
In a right-angled triangle, if two sides are given, the measure of the unknown angle can be known.
Since the value of opposite and adjacent sides are given, we use the tangent formula.
tan θ = 
✒ tan θ = 
✒ θ = 
(0.75)
✒ θ = 36.9°
✒ θ = 37°
Now let us find the other unknown angle 'x'.
We know that,
Sum of angles of a triangle = 180°
✒ 37° + x + 90° = 180° (90° since it is a right-angled triangle)
✒ x + 127° = 180°
✒ x = 180° - 127°
✒ x = 53°
Therefore, the three angles of the triangle are 37°, 53° and 90°.
Hence, the smallest angle is 37°.
Answer:
800.5×(2×20)=32020
Step-by-step explanation:
800.5×40=32020
Answer:
quadrant III (3)
Step-by-step explanation:
If you graph the point it is located in quadrant III
Part (a)
<h3>
Answer: Ø</h3>
This is the empty set
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Explanation:
It doesn't matter what set A is composed of. Intersecting any set with the empty set Ø will always result in the empty set.
This is because we're asking the question: "What does some set A and the empty set have in common?". The answer of course being "nothing" because there's nothing in Ø. Not even the value zero is in this set.
We can write Ø as { } which is a set of curly braces with nothing inside it.
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Part (b)
<h3>Answer: {1,2,3,4,5,6}</h3>
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Explanation:
When you union the universal set with any other set, you'll get the universal set.
The rule is 
where I've made B the universal set to avoid confusion of the letter U and the union symbol 
which looks nearly identical.
Why does this rule work? Well if an item is in set 
, then it's automatically in set U (everything is in set U; it's the universe). So we're not adding anything to the universe when applying a union involving this largest set.
It's like saying
- A = set of stuff inside a persons house
- = set of stuff outside a persons house (ie stuff that is not in set A)
- U = set of every item
we can see that 
will basically form the set of every item, aka the universal set.
