Answer:
0
Step-by-step explanation:
she took the same amount of money out of her account as she put in.
Answer:
90% confidence interval for the true proportion of air travelers who prefer the window seat is (0.575, 0.625)
Step-by-step explanation:
We have the following data:
Sample size = n = 1000
Proportion of travelers who prefer window seat = p = 60%
Standard Error = SE = 0.015
We need to construct a 90% confidence interval for the proportion of travelers who prefer window seat. Therefore, we will use One-sample z test about population proportion for constructing the confidence interval. The formula to calculate the confidence interval is:

Since, standard error is calculated as:

Re-writing the formula of confidence interval:

Here,
is the critical value for 90% confidence interval. From the z-table this value comes out to be 1.645.
Substituting all the values in the formula gives us:

Therefore, the 90% confidence interval for the true proportion of air travelers who prefer the window seat is (0.575, 0.625)
Answer:
fraction- 9/9=1
decimal- 1.0
percent- 100%
Step-by-step explanation:
Answer:
the answer is 2.
Step-by-step explanation:
i dont know how to explain sorry
It's the first choice. If you multiply the first equation by 3, your y term is a +12, and if you multiply the second equation by 4, your y term is a -12. When you add them the y terms cancel each other out.