A force of 182.6 lb should be applied to lift 700 lb object.
<h3>How to calculate the force?</h3>
Let the force required to lift be F
Total length = 29 in.
Distance of short end from pivot = in.
Distance from long end = 29-6 = 23 in.
Now Equating moments
F × 23 = 700x6
23F = 4200
F = 4200/23
= 182.6 lb
A force of 182.6 lb should be applied to lift 700 lb object.
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Answer:
b
Step-by-step explanation:
plus thanks for da pointz
Answer:
The 2 integers would be: 2 and 8
Step-by-step explanation:
2 + 8 = 10
Reciprocal of 2: 1/2
Reciprocal of 8: 1/8
1 / 2 - 1 / 8 = 4/8 - 1/8 = <u>3/8</u>
The Solution:
We are given the decimal below:
We are asked to express the given decimal as a fraction in its lowest term.
Therefore,
2(5y - 2) = 12 + 6y
7y - 4 = 12 + 6y ⇒ wrong, it has to be: 10y - 4 = 12 + 6y
so the correct answer is B
