The estimated product of two numbers, that are not multiples of ten is 2,800
Answer:
v+24
Step-by-step explanation:
I first drew a line with A in one side and C in the other side. Then, I put B in the middle, as it is the midpoint. Under AB, I put 4v, and under AC, I put 5v+24. To get BC, you must subtract 5v+24 and 4v. I did 5v+24-4v. All I really had to do was subtract 4v from 5v which gave me v, since I can only subtract like-term numbers. Anyway, after that, I got v+24. Hope this helped!
Answer: The answer is (C) 180°.
Step-by-step explanation: Given that m∠A = 40°. ∠B is a complement of ∠A and ∠C is a supplement of ∠B. We are to find m∠B + m∠C.
Since ∠B is a complement of ∠A, so we have
![m\angle A+m\angle B=90^\circ\\\\\Rightarrow m\angle B=90^\circ-m\angle A=90^\circ-40^\circ\\\\\Rightarrow m\angle B=50^\circ.](https://tex.z-dn.net/?f=m%5Cangle%20A%2Bm%5Cangle%20B%3D90%5E%5Ccirc%5C%5C%5C%5C%5CRightarrow%20m%5Cangle%20B%3D90%5E%5Ccirc-m%5Cangle%20A%3D90%5E%5Ccirc-40%5E%5Ccirc%5C%5C%5C%5C%5CRightarrow%20m%5Cangle%20B%3D50%5E%5Ccirc.)
Now, since ∠C is a supplement of ∠B, so we have
![m\angle B+m\angle C=180^\circ\\\\\Rightarrow m\angle C=180^\circ-m\angle B=180^\circ-50^\circ\\\\\Rightarrow m\angle C=130^\circ.](https://tex.z-dn.net/?f=m%5Cangle%20B%2Bm%5Cangle%20C%3D180%5E%5Ccirc%5C%5C%5C%5C%5CRightarrow%20m%5Cangle%20C%3D180%5E%5Ccirc-m%5Cangle%20B%3D180%5E%5Ccirc-50%5E%5Ccirc%5C%5C%5C%5C%5CRightarrow%20m%5Cangle%20C%3D130%5E%5Ccirc.)
Therefore,
![m\angle B+m\angle C=50^\circ+130^\circ=180^\circ.](https://tex.z-dn.net/?f=m%5Cangle%20B%2Bm%5Cangle%20C%3D50%5E%5Ccirc%2B130%5E%5Ccirc%3D180%5E%5Ccirc.)
Thus, (C) is the correct answer.
You can factor out a GCF of 7 out of all of the terms. The answer would be 7(3a+4b).