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3 years ago

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" title="s = ut + \frac{1}{2} at {}^{2} " alt="s = ut + \frac{1}{2} at {}^{2} " align="absmiddle" class="latex-formula">
Make 't' the subject of the formular

1 answer:

Dafna1 [17]3 years ago

7 0

Answer:

n=sx

Step-by-step explanation:

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Find the volume of the rectangular prism.<br> The volume is cm?<br><br> 8 cm<br> 5 cm<br> 9 cm

dedylja [7]

Answer:

360 cm

Step-by-step explanation:

volume= length x width x height

8*5*9=360 cm

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2 years ago

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Someone please help me with this ? Explain and give steps

Drupady [299]

Its an isosceles triangle

angle B = 47

and triangleADB is congruent to triangle ADC

from here we can say that BD = DC

now AD is a median and also altitude

so from here we can say angle x = 90

now in triangle ADB

90+47+y=180(ANGLE SUM PROPERTY )

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3 years ago

Engineers must consider the diameters of heads when designing helmets. The company researchers have determined that the populati

Margaret [11]

Answer:

1. The minimum head breadth that will fit the clientele is of 4.41-in.

2. The maximum head breadth that will fit the clientele is of 7.19-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 5.8-in and a standard deviation of 0.8-in.

This means that $\mu = 5.8, \sigma = 0.8$

1. What is the minimum head breadth that will fit the clientele?

The 4.1st percentile, that is, X when Z has a pvalue of 0.041, so X when Z = -1.74.

$Z = \frac{X - \mu}{\sigma}$

$-1.74 = \frac{X - 5.8}{0.8}$

$X - 5.8 = -1.74*0.8$

$X = 4.41$

The minimum head breadth that will fit the clientele is of 4.41-in.

2. What is the maximum head breadth that will fit the clientele?

100 - 4.1 = 95.9th percentile, that is, X when Z has a pvalue of 0.959, so X when Z = 1.74.

$Z = \frac{X - \mu}{\sigma}$

$1.74 = \frac{X - 5.8}{0.8}$

$X - 5.8 = 1.74*0.8$

$X = 7.19$

The maximum head breadth that will fit the clientele is of 7.19-in.

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2 years ago

Original price 32; markdown 12.5% what is the retail price

kobusy [5.1K]

Hello! The mark down is 12.5%, which means that will still have to pay a portion of the price. Mark down is a discount, where the price of the item goes down. To find the amount that needs to still be paid, subtract 12.5 from 100. 100 - 12.5 is 87.5 You still have to pay 87.5% of the price. Now, let's multiply that number by 32 to get the new price. 32 * 87.5% (0.875) is 28. There. The retail price is $28.

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3 years ago

Determine the longest interval in which the given initial value problem is certain to have a unique twice-differentiable solutio

natali 33 [55]

Answer:

answer in image. Thanks

Step-by-step explanation:

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2 years ago