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ladessa [460]
3 years ago
6

Please help

Mathematics
2 answers:
Elden [556K]3 years ago
7 0

Answer:

No

Step-by-step explanation:

By graphing this you can see that there is no right angle present

Andrei [34K]3 years ago
3 0

Answer:

I don't know just need points

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According to the given expression, the value of b if b^2=b^{-10}\\ is -1 and + 1

Indices are expressed using exponents and bases. Some of the useful laws of indices are:

a^m\times a^n=a^{m+n}\\a^{-n}=\frac{1}{a^n}

Given the expression;

b^2=b^{-10}\\

This can also be expressed as:

b^2=\frac{1}{b^{10}}\\b^2 \times b^{10} =1\\b^{2+10} =1\\b^{12}=1\\b=\pm\sqrt[12]{1}\\b=\pm1

Hence the value of b from the given indices is -1 and + 1

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