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enyata [817]
3 years ago
9

What are the solutions of the equation 2x2 = 2? Use a graph of the related function. A. There are two solutions: -1 and 1. B. Th

ere are two solutions: -1 and 1. C. There are two solutions: D. There are no real number solutions.

Mathematics
2 answers:
Lemur [1.5K]3 years ago
7 0
Hello :
2x² = 2
x²=1
x²-1=0
(x-1)(x+1) = 0
x-1=0 or x+1=0
x=1 or x= -1...(answer : <span>B. There are two solutions: -1 and 1 )</span>
Misha Larkins [42]3 years ago
4 0
<h2>Answer:</h2>

There are two solutions : -1 and 1.

<h2>Step-by-step explanation:</h2>

We are given equation in terms of variable  x as:

                  2x^2=2

On dividing both side of the equation by 2 we get the equation as:

                  x^2=1

This could also be written as:

                x^2-1=0

which is further written as:

(x-1)(x+1)=0

( Since, we have:

           a^2-b^2=(a-b)(a+b)    )

Hence, we have:

 x=1\ and\ x=-1

Hence, the graph of this equation ( i.e.  x^2-1=0 )will be point of intersection of:

  y=x^2-1 and y=0

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Sanja made a hole-in-one on the sixth hole of miniature golf 8 times and missed it 4 times. If Sanja attempts 24 more holes-in-o
hram777 [196]

Answer:

16 holes in ones

Step-by-step explanation:

I just did the guiz and got that one right

7 0
3 years ago
Read 2 more answers
Can anyone help me solve this Algebra 2 Problem, i literally cant figure it out
Andrews [41]

Answer:

Zeros : 1 , -1, 3

Degree : 4

End Behaviour : At x-> ∞ f(x) -> ∞ and x->-∞ f(x) -> ∞

Y - intercept : -3

Extra Points: (0,-3), (2,-3)

Step-by-step explanation:

f(x) = 0 to find the zeros

Therefore (x+1)(x-1)^{2} (x-3) = 0

Clearly x = -1,1,3

Here 1 is a repeating root as it is (x-1)²

Degree is highest power of x in f(x)

Clearly it is x*x²*x = x⁴ is the maximum power of x

Thus degree is 4

Looking at end behavior we substitute x->∞ and x-> -∞

Clearly f(x)>0 as all terms are positive and f(x)->∞

Similarly when x->-∞

f(x)>0 as 2 terms are -ve and their product is positive thus f(x)-> ∞

Y-Intercept is f(0)

f(0) = (0+1)(0-1)²(0-3) = 1*1*-3 = -3

Thus Y-Intercept is -3

Substitute x = 0 , 2 for extra points

Thus f(0) = -3

and f(2) = -3

Thus points on the graph (0,-3), (0,2)

We can use all this information to draw a graph remember that 1 is a repeating root so that will be a point of minima. The graph is a parabola that passes through x-axis at x = -1, 3.

5 0
3 years ago
Help please (will chose brainliest).
lara [203]
Answers with Explanation.


i. If we raise a number to an exponent of 1, we get the same number.

{10}^{1}  = 10

ii. If we raise 10 to an exponent of 2, it means we multiply 10 by itself two times.

{10}^{2}  = 10 \times 10 = 100

iii. If we raise 10 to an exponent of 3, it means we multiply 10 by itself three times.



{10}^{3}  = 10 \times  {10}^{2}  = 10 \times 100 = 1000

iv. If we raise 10 to an exponent of 4, it means we multiply 10 by itself four times.


{10}^{4}  =  10 \times {10}^{3} = 10 \times 1000 =  10000

v. If we raise 10 to an exponent of 5, it means we multiply 10 by itself five times.



{10}^{5}  = 10 \times  {10}^{4}  = 10 \times 10000 = 100000

{10}^{5}  = 100000

vi. Recall that,

{a}^{ - m}  =  \frac{1}{ {a}^{m} }
We apply this law of exponents to obtain,

{10}^{ - 2}  =  \frac{1}{{10}^{2} }  =  \frac{1}{100}

vii. We apply
{a}^{ - m}  =  \frac{1}{ {a}^{m} }
again to obtain,


{10}^{ - 3}  =  \frac{1}{ {10}^{3} }  =  \frac{1}{1000}





5 0
3 years ago
I started walking at 4pm when i finished walking the hour hand of the clock had turned 90 degrees what time did i finish walking
mars1129 [50]

Answer: 7 pm

Step-by-step explanation: Rotating the hour hand 90 degrees will be 3 hours. So 4 plus 3 = 7

7 0
3 years ago
The set of ordered pairs represents a
Murrr4er [49]

Answer:

The rule that represents the function is y=x^2+1 therefore the function is f(x)=x^2+1

Step-by-step explanation:

We have 5 ordered pairs in the plane xy. This means that <em>every pair has the form (x, y).</em>

Then, we have 5 values of x, which will give us 5 values of y, using the rule that represents the function.

<u>The easy evaluation is that when x=0, the value of y is y=1,</u> and then we can evaluate the rule for x=-1, and x=1, <em>the value of y is the same, y=2</em>. We can see here that we have a parabolic function, that is not centered in the origin of coordinates because when x=0, y=1.

So <u>we propose the rule </u>y=x^2+1<u> which is correct for the first 3 values of x.</u>

Now, <em>we evaluate the proposed rule when x=2, and when x=3</em>. This evaluations can be written as

f(2)=2^2+1=5

f(3)=3^2+1=10

Therefore, the rule is correct, and the function is

f(x)=x^2+1

8 0
3 years ago
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