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2 years ago

What is the denominator between 1/3 and 2/7

1 answer:

6 0

I find it's easiest to find the middle of numbers with a simple trick I learned just today!

First, you find out how much the distance is between the two numbers.

0-1-2-3-4-5-6-7

If you count, there is a distance of four in between 3 and 7. So we do the next step.

In the next step, all you need to do is split the distance of the numbers in half. Then we can subtract half fro the bigger number or add the half to the smaller half.

4 / 2 = 2
7 - 2= 5, or 3 + 2 = 5

So the denominator between 1/3 and 2/7 is 0/5. You can add any number you want to the top I think.

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weqwewe [10]

Answer: sounds sweet:)

Step-by-step explanation:

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3 years ago

How can the x-intercept and y-intercept be used to graph a linear equation

JulijaS [17]

Because a line always goes past the y-intercept and x-intercept. It's not always both, it can sometimes just be the x-intercept or the y-intercept.

When a line intersects these points, for example if a line was to intersect the x-axis then y would be equal to 0, and the opposite for the y-axis. If a line was to intersect the y-axis x would be equal to 0.

Therefore by using that knowledge, and the equation of the line [ y=mx+c or y-y1=m(x-x1) ], we can find the equation of our line. Of course you would need the gradient of that line (the value "m").

5 0

3 years ago

PLEASE HELP ASAP:

weqwewe [10]

Answer:

top right is alternate interior and top left is corresponding

Step-by-step explanation:

8 0

3 years ago

4x^2-7x=15<br> Solve by factoring and please please please explain or show the work

vodomira [7]

Answer:

x=3 and x=-1.25

Step-by-step explanation:

4x^2-7x=15

subtract 15 from each side:

4x^2-7x-15=0

factor (trying different numbers that the sum is 7 and the quotient is 15)

(2x-6 )(2x+2.5 )=0

2x-6=0 add 6 to each side

2x=6

x=3

2x+2.5=0 subtract 2.5 from each side

2x=-2.5

x=-1.25

8 0

3 years ago

In one year the perseid metor shower had a metor appear every 1/5 5 minutes on average That same year the Leonid metor shower ha

olga55 [171]

In one year, the Perseid meteor shower had a meteor appear every 1 1/5 minutes on average. That same year, the Leonid meteor shower had a meteor appear every 4 2/3 minutes on average. How many more meteors fell during the Perseid meteor shower?

Answer:

325,452 meteors

Step-by-step explanation:

We all know that :

We have 365 days in a year and in each day there are 24 hours, Likewise an hour has 60 minutes

SO, the total number of minutes in a year is :

365 × 24 × 60 = 525600 minutes

For Perseid meteor:

$1 + \frac{1}{5} \\ \\ = 1 + 0.2 \\ \\ = 1.2$

So one meteor fall at 1.2 minutes interval Thus, in a year, we will have :

1 meteor - 1.2 minutes.

x meteor - 525600 minutes.

1.2x = 525600

$x = \frac{525600}{1.2}$

x = 438000

∴ 438,000 meteors fell during the Perseid shower.

For Leonid meteor shower:

$4 + \frac{2}{3} = 4.67$

So one meteor fall at 4.67 minutes interval Thus, in a year, we will have :

1 meteor - 4.67 minutes.

x meteors - 525600 minutes.

$4.67x = 525600$

$x = \frac{525600}{4.67}$

x = 112548

112,548 meteors fell during the Leonid Shower.

Finally , the numbers of more meteors that fell during the Perseid meteor shower is calculated by the difference in the number of Perseid meteor shower and Lenoid meteor shower. i.e

438,000 - 112,548 = 325,452

325,452 more meteors fell during the Perseid meteor shower

5 0

3 years ago