2 years ago

What percent of $20,574.50 equals $1,180.47

Mathematics

1 answer:

igor_vitrenko [27]2 years ago

7 0

5.737539186% rounded to the nearest tenth its 5.7%

You might be interested in

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!

Rashid [163]

$x = \frac{ -2 \pm \: \sqrt{ {2}^{2} - 4 \times 1 \times 10 } }{2} \\ \\ x = \frac{ - 2 \pm 6i}{2} \\ \\ \boxed{ \red{ \huge{x = - 1 \pm \: 3i}}}$

$\boxed{ \red{ \huge{answer = d}}}$

3 0

3 years ago

MARK AS BRAINLIESTT

Lelu [443]

Answer

B) x + 20 ≥ 50

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Andrea has 18 yards of fabric. How many 4-inch pieces can she cut from her original piece?

Mrac [35]

Answer:

162 pieces

Step-by-step explanation:

Andrea has 18 yards

How many 4 inch pieces can she get?

Convert

1 yard = 3 feet

18 yards = 54 feet

1 foot = 12 inches

54 feet = 648 inches

Divide

648 inches ÷ 4 inches = 162 pieces

Hope this helps :)

6 0

3 years ago

Read 2 more answers

Select the correct answer.

zhannawk [14.2K]

You have a good day and good luck on that question

8 0

2 years ago

Suppose that the hourly wages of fast food workers are normally distributed with an unknown mean and standard deviation. The wag

Nutka1998 [239]

Answer: 1.303639

Step-by-step explanation:

The t-score for a level of confidence $(1-\alpha)$ is given by :_

$t_{(df,\alpha/2)}$ , where df is the degree of freedom and $\alpha$ is the significance level.

Given : Level of significance : $1-\alpha:0.80$

Then , significance level : $\alpha: 1-0.80=0.20$

Sample size : $n=40$

Then , the degree of freedom for t-distribution: $df=n-1=40-1=39$

Using the normal t-distribution table, we have

$t_{(df,\alpha/2)}=t_{39,0.10}=1.303639$

Thus, the t-score should be used to find the 80% confidence interval for the population mean =1.303639

8 0

2 years ago