Answer:
In Tyler scale, 1 inch equals 4 ft.
Step-by-step explanation:
Giving the following information:
Tyler made a scale drawing of a 24 ft longboat. In his drawing, the boat was 6 inches.
<u>We know that 1 ft is 12 inches. Therefore, 24 ft:</u>
24*12= 288 inches
<u>Now, we have to determine the scale that Tyler used.</u>
<u></u>
1 Tyler inch= 288/6= 48 inches
In ft:
1 Tyler inch= 48/12= 4 ft
In Tyler scale, 1 inch equals 4 ft.
Mean:
E[Y] = E[3X₁ + X₂]
E[Y] = 3 E[X₁] + E[X₂]
E[Y] = 3µ + µ
E[Y] = 4µ
Variance:
Var[Y] = Var[3X₁ + X₂]
Var[Y] = 3² Var[X₁] + 2 Covar[X₁, X₂] + 1² Var[X₂]
(the covariance is 0 since X₁ and X₂ are independent)
Var[Y] = 9 Var[X₁] + Var[X₂]
Var[Y] = 9σ² + σ²
Var[Y] = 10σ²
Answer:
$18
Step-by-step explanation:
1. Subtract 5-2 to get three
2. Divide 27 by three to get 9. Now you know how many $ is in one sectio
3. Multiply 9 by 2
4. Riley got $18
Answer:
-4n2+24n-9
Step-by-step explanation:
multiply each term by -4 to get -4n2+24n-9
Using Pythagoras's theorem, we can get that 60 inches is the hypotenuse and 52 inches is one of the legs. 60^2 - 52^2 = b^2, where b is the leg that we are trying to find, aka the length of the shadow. We find that b^2 = 896. The square root of 896 is closest to 30 inches, therefore the answer is A) 30 inches
