We can do this easily using 0s.
(x - i) (x + i) (x + 4) (x - 1) = 0
If you plug in any of the numbers, you'll get 0, making the equation true.
Answer:
(4x + 7y)(4x - 7y)
Step-by-step explanation:
Rewrite 16 as 4^2
= 4^2x^2 - 49y^2
Rewrite 49 as 7^2
= 4^2x^2 - 7^2y^2
Apply the Exponent Rule Pt 1 ((a^m*b^m =(ab)^m))
= (4x)^2 - 7^2y^2
Apply the Exponent Rule Pt 2
= (4x)^2 - (7y)^2
Apply Difference of Squares Formula (( x^2-y^2 = (x + y)(x - y)
= (4x + 7y) (4x - 7y)
Answer:
2
Step-by-step explanation:
2^{4-3}
=2