Chris drove 240 miles using 9 gallons of gas. At this rate, how many gallons of gas would he need to drive 216 miles?

coldgirl [10]

Three times larger.

This is because you have to multiply 2m (the smaller prism) by three to get 6m (on the bigger prism), then you will find that if you multiply the rest of the numbers (on the smaller prism) by three you will get the exact numbers that are on the big prism. Hope this helps!

8 0

3 years ago

Read 2 more answers

Two times colleen’s age plus three times Ashley’s age equals 108. Colleen’s age is three times Ashley’s age. How old is Colleen

sineoko [7]

Answer: 36

Step-by-step explanation: 2x36=72. 36/3=12. 3x12=36. 36+72=108.

6 0

2 years ago

Read 2 more answers

HELP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!

Umnica [9.8K]

Answer:

It would be -3

-5 = (-8) - (-3)

6 0

2 years ago

What is the volume of a cone with a base of 10 and height of 9

Leto [7]

The formula being used is V= $\pi$ r^2(h/3)

V≈235

V=235.62 to be approximate

5 0

3 years ago

Find the function y = f(t) passing through the point (0, 18) with the given first derivative.

monitta

Answer:

$\displaystyle y = \frac{t^2}{16} + 18$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Functions
Function Notation
Coordinates (x, y)

Calculus

Derivatives

Derivative Notation

Antiderivatives - Integrals

Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

Point (0, 18)

$\displaystyle \frac{dy}{dt} = \frac{1}{8} t$

Step 2: Find General Solution

Use integration

[Derivative] Rewrite: $\displaystyle dy = \frac{1}{8} t\ dt$
[Equality Property] Integrate both sides: $\displaystyle \int dy = \int {\frac{1}{8} t} \, dt$
[Left Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \int {\frac{1}{8} t} \, dt$
[Right Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle y = \frac{1}{8}\int {t} \, dt$
[Right Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \frac{1}{8}(\frac{t^2}{2}) + C$
Multiply: $\displaystyle y = \frac{t^2}{16} + C$