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ch4aika [34]
3 years ago
9

What is the arc length if

Mathematics
1 answer:
dem82 [27]3 years ago
6 0

Answer:

A. 8π / 3

Step-by-step explanation:

You might be interested in
45.15 divied by 21 equal but the estimate
pav-90 [236]

Answer:

The answer is 2.00.

Step-by-step explanation:

45.15 ÷ 21 = 2.15

2.15 rounded off to the nearest whole number is 2.00.

This was because you asked for an estimate.^

3 0
2 years ago
X 0 2 10 20
prisoha [69]


Use two points from the graph to check if they are constant. In this case let’s use (0,50) & (2,58)

To find slope you have to do the following.

y2-y1 / x2-x1

Plug in the values, 58-50/2-0
This gives you 4.

When you use two other points, in this case (10,90) (20,130) you get a slope of 4.

This means the slope is 4.

We are trying to get an equation of y=mx+b.
We have slope already which is 4. So now we plug in y=4x + b

Now we need to find b. There is an equation to solve for b. Which is b=y1-m(x1)

But b is the y-intercept so there is already a B which is 50

So the table IS a linear equation and the equation is y=4x+50.
8 0
3 years ago
A box contains 2 red marbles , 3 green marbles , and 3 blue marbles
krek1111 [17]

Answer:

the box contains a total of 8 marbles .

although if you understand pixels then you would know that could stand for RGB so your color would be a very dark greenish brown

Step-by-step explanation:

no question?

5 0
3 years ago
What is the GCF of 24,48m
Phoenix [80]
24
It goes into 24 once and into 48 twice
3 0
3 years ago
Read 2 more answers
Find the area of quadrilateral ABCD
andreev551 [17]

Answer:

<em>A ≈ 28.5</em>

Step-by-step explanation:

a, b, c

P = a + b + c

Semiperimeter s = \frac{a+b+c}{2}

A = \sqrt{s(s-a)(s-b)(s-c)}

~~~~~~~~~~~~~~~

P_{ABC} = 4.3 + 2.89 + 6.81 = 14

s = 14 ÷ 2 = 7

A_{ABC} = \sqrt{7(7-4.3)(7-2.89)(7-6.81)} = √14.75901 ≈ 3.84

P_{BCD} = 8.59 + 7.58 + 6.81 = 22.98

s = 22.98 ÷ 2 = 11.49

A_{BCD} = \sqrt{11.49(11.49-8.59)(11.49-7.58)(11.49-6.81)} = √609.7343148 ≈ 24.6928

A_{ABCD} = 3.84 + 24.6928 ≈ <em>28.5</em>

3 0
2 years ago
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