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umka2103 [35]
3 years ago
8

Which of the following expressions has a coefficient of 10 and a constant of 5

Mathematics
1 answer:
Readme [11.4K]3 years ago
7 0
Third option is correct
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Howie wants to get a car loan with 4% simple interest rate. If the car costs $25,000, how much would Howie need to pay back at t
likoan [24]

The amount Howie will pay back at the end of one year is $26000.00

The given parameters are:

P =25000 -- the principal amount

R = 4\% -- the interest rate

T=1 --- the duration

The amount to pay back in this duration is then calculated using:

A = P(1 + RT)

So, we have:

A = 25000(1 + 4\% \times 1)

A = 25000(1 + 4\% )

Express percentage as decimal

A = 25000(1 + 0.04)

A = 25000(1 .04)\\

Multiply

A = 26000

Hence, the amount to pay back is $26000.00

Read more about simple interest at:

brainly.com/question/1115815

7 0
3 years ago
What is the value of f(2)?
Lunna [17]

Question:

What is the equation?

6 0
3 years ago
Solve the following integral.<br><br> <img src="https://tex.z-dn.net/?f=%5Cint4x%5Ccos%282-3x%29dx" id="TexFormula1" title="\int
bagirrra123 [75]

Hi there!

\boxed{-\frac{4x}{3}sin(2-3x) + \frac{4}{9}cos(2-3x) + C}

To find the indefinite integral, we must integrate by parts.

Let "u" be the expression most easily differentiated, and "dv" the remaining expression. Take the derivative of "u" and the integral of "dv":

u = 4x

du = 4

dv = cos(2 - 3x)

v = 1/3sin(2 - 3x)

Write into the format:

∫udv = uv - ∫vdu

Thus, utilize the solved for expressions above:

4x · (-1/3sin(2 - 3x)) -∫ 4(1/3sin(2 - 3x))dx

Simplify:

-4x/3 sin(2 - 3x) - ∫ 4/3sin(2 - 3x)dx

Integrate the integral:

∫4/3(sin(2 - 3x)dx

u = 2 - 3x

du = -3dx ⇒ -1/3du = dx

-1/3∫ 4/3(sin(2 - 3x)dx ⇒ -4/9cos(2 - 3x) + C

Combine:

-\frac{4x}{3}sin(2-3x) + \frac{4}{9}cos(2-3x) + C

7 0
3 years ago
Read 2 more answers
Given the coordinates of A(3, 6), B(5, 2), and C(9, 4), which coordinates for D make ABCD a square?
tankabanditka [31]

Answer:

(7,8)

Step-by-step explanation:

6 0
3 years ago
Please help!! What Find the Error and explain why it is wrong!
Nata [24]

Answer:

First image attached

The error was done in Step E, because student did not multiply 2\cdot x -8 by the negative sign in numerator. Step E must be \frac{2\cdot x -5}{(x+4)\cdot (x-4)}.

Second image attached

The error was done in Step C, because the student omitted the 2\cdot a \cdot b of the algebraic identity (a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}. Step C must be 5\cdot x = x^{2}+4\cdot x + 4

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply 2\cdot x -8 by the negative sign in numerator. The real numerator in Step E should be:

3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x

Hence, Step E must be \frac{2\cdot x -5}{(x+4)\cdot (x-4)}.

Second image attached

The error was done in Step C, because the student omitted the 2\cdot a \cdot b of the algebraic identity (a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}. Step C must be 5\cdot x = x^{2}+4\cdot x + 4

And further steps are described below:

Step D

x^{2}-x+4 = 0

Which according to the Quadratic Formula, represents a polynomial with complex roots. That is: (a = 1, b = -1, c = 4)

D = b^{2}-4\cdot a\cdot c

D = (-1)-4\cdot (1)\cdot (4)

D = -17 (Conjugated complex roots)

Step E

(x-0.5-i\,1.936)\cdot (x-0.5+i\,1.936) = 0

Step F

x = 0.5+i\,1.936\,\lor\,x = 0.5-i\,1.936

8 0
3 years ago
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