<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B3x%20%2B%2013%7D%20%20%3D%20%20%5Csqrt%7B6x%20%2B%201%7D%20" id="TexFormula1" tit

3 years ago

le=" \sqrt{3x + 13} = \sqrt{6x + 1} " alt=" \sqrt{3x + 13} = \sqrt{6x + 1} " align="absmiddle" class="latex-formula">
3х + 13 = 6х +1

Mathematics

2 answers:

emmainna [20.7K]3 years ago

8 0

Answer:

solution given;

$\sqrt{3x + 13} = \sqrt{6x + 1}$

3х + 13 = 6х +1

13-1=6x-3x

3x=12

x= $\frac{12}{3}$ =4

x=4

mars1129 [50]3 years ago

5 0

Step-by-step explanation:

hope it is helpful to you

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