Question

le=" \sqrt{3x + 13} = \sqrt{6x + 1} " alt=" \sqrt{3x + 13} = \sqrt{6x + 1} " align="absmiddle" class="latex-formula">
3х + 13 = 6х +1​

Answer 1

Answer:

solution given;

$\sqrt{3x + 13} = \sqrt{6x + 1}$

3х + 13 = 6х +1

13-1=6x-3x

3x=12

x=$\frac{12}{3}$=4

x=4

Answer 2

Step-by-step explanation:

hope it is helpful to you