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LenaWriter [7]
3 years ago
5

le=" \sqrt{3x + 13} = \sqrt{6x + 1} " alt=" \sqrt{3x + 13} = \sqrt{6x + 1} " align="absmiddle" class="latex-formula">
3х + 13 = 6х +1​
Mathematics
2 answers:
emmainna [20.7K]3 years ago
8 0

Answer:

solution given;

\sqrt{3x + 13} = \sqrt{6x + 1}

3х + 13 = 6х +1

13-1=6x-3x

3x=12

x=\frac{12}{3}=4

x=4

mars1129 [50]3 years ago
5 0

Step-by-step explanation:

hope it is helpful to you

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============================================================

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-----------

Note: in this step, I cross multiplied. The general template for cross multiplication is that we go from A/B = C/D to A*D = B*C. As the name implies, the "cross" refers to the "X" shape that forms when you multiply the terms.

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