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evablogger [386]

3 years ago

12

What is the sum of 5 feet 9 inches and 12 feet 3 inches

2 answers:

OlgaM077 [116]3 years ago

8 0

The answer is 18 feet.

mestny [16]3 years ago

6 0

5 ft + 12 ft = 17 ft

<span>9 in + 3 in = 12 in = 1 ft </span>

<span>17 ft + 1 ft = 18 ft
</span>hope this helps

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n200080 [17]

2^2. 2 and 2. Because 2 and 2

8 0

3 years ago

A. The ratio of the number of boys

s344n2d4d5 [400]

Answer:

the girls = 18

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6×4=24

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3 years ago

Hey guys please help with this questoin Find (x+y) ÷ (x-y) if x=5/4 y=-1/3

pogonyaev

Answer:

<h2>11/19</h2>

Step-by-step explanation:

$(\frac{5}{4} + (-\frac{1}{3})) \div (\frac{5}{4} - (-\frac{1}{3}))\\\\\frac{\frac{5}{4}+\left(-\frac{1}{3}\right)}{\frac{5}{4}-\left(-\frac{1}{3}\right)}\\\\\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a,\:-\left(-a\right)=a\\=\frac{\frac{5}{4}-\frac{1}{3}}{\frac{5}{4}+\frac{1}{3}}\\\\\mathrm{Join}\:\frac{5}{4}+\frac{1}{3}:\quad \frac{19}{12}\\\mathrm{Join}\:\frac{5}{4}-\frac{1}{3}:\quad \frac{11}{12}\\\\=\frac{\frac{11}{12}}{\frac{19}{12}}\\\\=\frac{11\times\:12}{12\times \:19}$

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7 0

4 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago

Please answer!!! Will mark brainliest answer !!!

kenny6666 [7]

Answer:

A, D

Step-by-step explanation:

When we multiply the fractions, we can get:

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This is also equivalent to:

$5^{-4}$

When looking at the answer choices, the only ones that equal $5^{-4}$ are A and D because:

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$5^{2}*5^{-6} = 5^{-4}$

3 0

3 years ago