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elena-14-01-66 [18.8K]
3 years ago
7

What are the amplitude, period, and midline of f(x) = 3 cos(4x − π) + 2?

Mathematics
2 answers:
Kruka [31]3 years ago
8 0

Answer:

The amplitude of the function is 3, period of the function is \frac{\pi}{2} and midline of the function is 2.

Step-by-step explanation:

The given function is

f(x)=3\cos(4x-\pi)+2               .... (1)

The standard form of a Cosine function is

g(x)=a\cos(bx+c)+d               ... (2)

where, a is amplitude, period is \frac{2\pi}{b} and d is midline.

From (1) and (2), we get

a=3,b=4,d=2

The amplitude of the function is

a=3

The period of the function is

\frac{2\pi}{b}=\frac{2\pi}{4}=\frac{\pi}{2}

The midline of the function is

d=2

Therefore the amplitude of the function is 3, period of the function is \frac{\pi}{2} and midline of the function is 2.

Fudgin [204]3 years ago
7 0
<span>Amplitude: 3; period: pi/2; midline: y = 2</span>
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emmasim [6.3K]

Answer:

Width = 11 yards

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Step-by-step explanation:

First of all, the length of the rectangle is 6 yards longer than the width, this means, length = width + 6 yards. This dimensions can be represented on figure 1, where <em>w</em> is width, and <em>l</em>, for length.

We know the area of a rectangle is A = width x length

For our case 187 = w . (w + 6)

Using the Distributive Property for the multiplication we obtain

187 = w^{2} +6w

w^{2} +6w-187 =0,

Using the quadratic formula w=\frac{-b\±\sqrt{b^{2}-4ac } }{2a} where a = 1, b = 6, c = - 187 and replacing into the formula, we will have:

w=\frac{-6\±\sqrt{6^2-4(1)(-187)} }{2(1)}

w=\frac{-6\±\sqrt{36+748} }{2}=\frac{-6\±\sqrt{784} }{2}=\frac{-6\±28}{2}

We have two options: w=\frac{-6+28}{2}=\frac{22}{2}=11  yards

Or

w=\frac{-6-28}{2}=\frac{-34}{2}=-17 yards But a distance (width) can not be negative so, this answer for w must be discarded.

The answer must be width = 11 yards.

To find the length l =\frac{187}{11}=17 yards

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x+5^3

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Find all sides of a right triangle whose perimeter is equal to 60 cm and its area is equal to 150 square cm
miskamm [114]

Answer:

15cm by 20cm by 25cm

Step-by-step explanation:

Let the sides of the right angle be x, y and h

x is the breadth

y is the height

h is the hypotenuse

Perimeter = x + y + h

x + y +h  = 60

x+y = 60-h .... 1

If its area is equal to 150 square cm, then;

Area = 1/2 * base * height

Area = 1/2 *x * y

xy/2 = 150

xy = 300 ....2

According to pythagoras theorem;

x² + y² = h²

On expanding x² + y²

x² + y² = (x+y)² - 2xy

The equation becomes

(x+y)² - 2xy = h² ... 3

Substitute equation 1 and 2 into 3;

From 3;

(x+y)² - 2xy = h² ... 3

(60-h)² - 2(300) = h²

3600-120h + h² - 600 = h²

3600-120h - 600 = 0

-120h = 600-3600

-120h = -3000

h = 3000/120

h = 25cm

Recall that x+y+h = 60

x+y+25 = 60

x+y = 60 - 25

x+y = 35 ... 4

From equation 2;

xy = 300

x = 300/y ..... 5

Substitute 5 into 4;

300/y + y = 35

(300+y²)/y = 35

300+y² = 35y

y²-35y + 300 = 0

y²-20y-15y + 300 = 0

y(y-20)-15(y-20) = 0

y-20 = 0 and y - 15 =0

y = 20 and 15

since x+y = 35

x + 20 = 35

x = 35 - 20

x = 15

Hence the sides of the triangle are 15cm by 20cm by 25cm

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