Treat x^4 as the square of p: x^4 = p^2.
Then x^4 - 5x^2 - 36 = 0 becomes p^2 - 5p - 36 = 0.
This factors nicely, to (p-9)(p+4) = 0. Then p = 9 and p = -4.
Equating 9 and x^2, we find that x=3 or x=-3.
Equating -4 and x^2, we see that there's no real solution.
Show that both x=3 and x=-3 are real roots of x^4 - 5x^2 - 36 = 0.
3(1) - 8 = 3 - 8 = -5
just plug in 1 for x that's what f(1) means
Answer:
Step-by-step explanation:
Let a = - 1 2/5 and b = 2 1/3
<u>We have a + b, lets compare with the options:</u>
- A) a + (- b) = a - b, no
- B) a - b, no
- C) b + a = a + b, yes
- D) b - a, no
Answer:
19.775
Step-by-step explanation:
I assume your asking which number goes the most in depth to find that look for the number that has the most decimal places
