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GrogVix [38]
3 years ago
14

Please help im desperate no. 48 and 49​

Mathematics
2 answers:
stealth61 [152]3 years ago
8 0

Answer:

C and (3, 6 )

Step-by-step explanation:

(48)

Since given y = 2x the best method of solving is by substitution C

(49)

Given the 2 equations

3x + y = 15 → (1)

y = 2x → (2)

Substitute y = 2x into (1)

3x + 2x = 15

5x = 15 ( divide both sides by 5 )

x = 3

Substitute x = 3 into (2) and evaluate for y

y = 2x = 2 × 3 = 6

solution is (3, 6 )

exis [7]3 years ago
3 0

Answer:

48. option C : Substitution

49. Option D :  ( 3, 6)

Step-by-step explanation:

3x + y = 15       ------------- ( 1 )

      y = 2x  ------------------- ( 2 )

Substitute ( 2 ) in ( 1 ) :

3x + y = 15

3x + 2x = 15

5x = 15

x = \frac{15}{5} = 3

Substitute x in ( 2 ) :

y = 2x

y = 2 × 3 = 6

The solution to the system of equation is ( 3 , 6 )  

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Find the distance between the points A and B. If necessary, round to the nearest tenth.
klemol [59]

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1. 26.2

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Hiroshi has 4 engines and 18 box cars. Find the ratio of engines to box cars. Write the ratio as a fraction in simplest form.
lyudmila [28]
To write a ratio as a fraction, we simply take the first number in the ratio and make it the numerator while taking the second number in the ratio and making it the denominator.

Because we want the ratio of engines to box cars, our ratio should be:

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When we substitute in our respective values, we get:

4/18

To simplify this ratio, we have to find the GCF, or greatest common factor of the numerator and the denominator, which in this case is 2. To simplify, we divide both the numerator and the denominator by the GCF, as follows:

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2/9

Therefore, your answer is 2/9.

Hope this helps!
4 0
3 years ago
A boxer is put on a diet to gain 20 lb in four weeks. The boxer gains 4 1/3 lb the first week and 5 5/6 lb the second week. How
V125BC [204]

Answer:

9.8 lbs

Step-by-step explanation:

4 1/3 + 5 5/6= 10 1/6

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7 0
3 years ago
PYTHAGORAS THEROM AND TRIGONOMETRY RATIO​
marysya [2.9K]

Answer:

1) ΔACD is a right triangle at C

=> sin 32° = AC/15

⇔ AC = sin 32°.15 ≈ 7.9 (cm)

2) ΔABC is a right triangle at C, using Pythagoras theorem, we have:

AB² = AC² + BC²

⇔ AB² = 7.9² + 9.7² = 156.5

⇒ AB = 12.5 (cm)

3)  ΔABC is a right triangle at C

=> sin ∠BAC = BC/AB

⇔ sin ∠BAC = 9.7/12.5 = 0.776

⇒ ∠BAC ≈ 50.9°

4) ΔACD is a right triangle at C

=> cos 32° = CD/15

⇔ CD = cos32°.15

⇒ CD ≈ 12.72 (cm)

Step-by-step explanation:

7 0
3 years ago
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