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grandymaker [24]
2 years ago
15

Why would immigrints have chosen to live in the middle colonies

Mathematics
1 answer:
salantis [7]2 years ago
7 0

Answer:

the immigrants would have chosen to live in the middle colonies because they had lots of crops and fertile soil

You might be interested in
A rectangular prism with the volume of 10 cubic units is filled with cubes with side links of 1/2 unit how many 1/2 unit kids do
ELEN [110]
Answer 80
Required cubes 10/1/8=80
8 0
3 years ago
Suppose the horses in a large stable have a mean weight of 975lbs, and a standard deviation of 52lbs. What is the probability th
Lubov Fominskaja [6]

Answer:

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 975, \sigma = 52, n = 31, s = \frac{52}{\sqrt{31}} = 9.34

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable?

pvalue of Z when X = 975 + 15 = 990 subtracted by the pvalue of Z when X = 975 - 15 = 960. So

X = 990

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{990 - 975}{9.34}

Z = 1.61

Z = 1.61 has a pvalue of 0.9463

X = 960

Z = \frac{X - \mu}{s}

Z = \frac{960 - 975}{9.34}

Z = -1.61

Z = -1.61 has a pvalue of 0.0537

0.9463 - 0.0537 = 0.8926

0.8926 = 89.26% probability that the mean weight of the sample of horses would differ from the population mean by less than 15lbs if 31 horses are sampled at random from the stable

7 0
3 years ago
Determine whether the given value is a solution of the equation.
nlexa [21]

Answer:

16 is not the solution to the equation

Step-by-step explanation:

5 0
3 years ago
If the statement "If it is cold, then I wear a jacket" is assumed to be true, is its converse, "If I wear a jacket, then it must
Ad libitum [116K]

it is false, there could be other reasons they wear a jacket other than being cold.

8 0
3 years ago
In recent years, 23.8% of all registered doctors were female. If there were 57,800 female registered doctors that year, what was
PilotLPTM [1.2K]
57,800 is 23.8% of the total number of registered doctors.

To find out the number of registered doctors, we divide the number of female doctors by 23.8% as a decimal (which is just 0.238):

57,800 ÷ 0.238 = 242,857
-------------------------------------------------------------------------------------------------------------
Answer:

So there are 242,857 registered doctors.
6 0
3 years ago
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