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lbvjy [14]
3 years ago
13

Is the following relation a function?O Yes O No​

Mathematics
1 answer:
posledela3 years ago
3 0
No its not a function
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Mr. Green’s lawnmower holds 600milliliters of gasoline in the tank. He just filled his 6-liter gas can at the station. How many
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Step-by-step explanation:

1 litre = 1000 ml

6 litres = 6000 ml

Lawnmover holds 600 ml

So 6000 ml will fill

6000/600 = 10 times

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The area of the rectangle below is ___sq. units.
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Answer: Let's have the picture of the rectangle

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4 years ago
Write the given expression as an algebraic expression in x. tan(2 cos^-1(x))
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\bf tan\left[ 2cos^{-1}(x) \right]\implies tan\left[ 2cos^{-1}\left( \frac{x}{1} \right) \right]
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\textit{if we say }cos^{-1}\left( \frac{x}{1} \right)=\theta\textit{  that means }tan\left[ 2cos^{-1}\left( \frac{x}{1} \right) \right]\iff tan(2\theta)\\\\
-----------------------------\\\\
cos^{-1}\left( \frac{x}{1} \right)=\theta\implies cos(\theta)=\cfrac{x}{1}\cfrac{\leftarrow adjacent=a}{\leftarrow hypotenuse=c}\\\\
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\bf \textit{again, using the pythagorean theorem to get the opposite side}
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c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b\implies \pm\sqrt{1^2-x^2}=b
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\pm\sqrt{1-x^2}=b\\\\
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tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\implies tan(2\theta)=\cfrac{2\cdot \frac{\pm\sqrt{1-x^2}}{x}}{1-\left( \frac{\pm\sqrt{1-x^2}}{x} \right)^2}
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\bf tan(2\theta)=\cfrac{\frac{\pm2\sqrt{1-x^2}}{x}}{1-\frac{1-x}{x}}\implies 
tan(2\theta)=\cfrac{\frac{\pm2\sqrt{1-x^2}}{x}}{\frac{x-1+x}{x}}
\\\\\\
tan(2\theta)=\cfrac{\pm2\sqrt{1-x^2}}{x}\cdot \cfrac{x}{2x-1}
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tan(2\theta)=\cfrac{\pm 2\sqrt{1-x^2}}{2x-1}


6 0
4 years ago
Which of the following is the range of function based on the input-output table below.
tamaranim1 [39]

Answer:

B)  {1000, 1100, 1200, 1300, 1400, 1500, 1600}


Step-by-step explanation:

Domain is the set of x values (input)

and

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In this case, y = pay per month

so Range = {1000, 1100, 1200, 1300, 1400, 1500, 1600}

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