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antoniya [11.8K]
3 years ago
8

Number that is greater than 714,587

Mathematics
1 answer:
Reptile [31]3 years ago
8 0
That can be expressed algebraically as x >714,587
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a. The position of a particle is given by x(t) = t3 - 3t2 - 96 +1. For what values oft is the particle at rest?
natita [175]

Answer:

 t = 0 and t = 2

Step-by-step explanation:

It is at rest when the velocity = 0

The velocity is the 1st derivative

So, x'(t) = 3t^2 - 6t = 0

                3t(t - 2) = 0

                  t = 0 and t = 2

6 0
3 years ago
The sum of my number and two and two thirds is seven. What is my number?
aniked [119]

Answer:

1,2,3,5

Step-by-step explanation:

3 0
3 years ago
4x + 2(x − 3) = 3x + x − 12<br> find the answer for x
Nitella [24]
X=  -3...................
7 0
3 years ago
From a thin piece of cardboard 50 in. by 50 in., square corners are cut out so that the sides can be folded up to make a box. Wh
mixer [17]

Answer:

When dimension of box is 33.33 inches × 33.33 inches ×8.33  then its volume is maximum and is 9259.26 cubic inches.

Step-by-step explanation:

Let h be the length (in inches) of the square corners that has been cut out from the cardboard and that would be the height of the cardboard box.

Since the squares have been cut from cardboard, both sides of the cardboard would reduce by 2h.

Thus, The dimension of box is  (50 – 2h) × (50 – 2h) × h in dimensions.

The volume V of rectangular box = (Length × Breadth × Height) cubic inches.

V=(50-2h) \times (50-2h) \times h

V=(50-2h)^2 \times h  ..............(1)

Using (a-b)^2=a^2+b^2-2ab

V=h(2500+4h^2-200h)

V=2500h+4h^3-200h^2

For obtaining a box of maximum volume, maximize V as a function of h.


Differentiate both sides with respect to h,

\frac{dV}{dh}=2500+12h^2-400h

\frac{dV}{dh}=4(625+3h^2-100h)

Solving quadratic equation,625+3h^2-100h

\frac{dV}{dh}=4(3h^2-25h-75h+625)

\frac{dV}{dh}=4(h(3h-25)-25(3h-25))

\frac{dV}{dh}=4((h-25)(3h-25))

For maximum, \frac{dV}{dh}=0  

thus,4((h-25)(3h-25))=0

⇒ h= 25 or h=\frac{25}{3}

Now check (1) for h= 25 and h=\frac{25}{3}.

h= 25 is not possible as when h is 25 inches then length and breadth becomes 0.

When h=\frac{25}{3}.

(1) ⇒ V=(50-2(\frac{25}{3}))^2 \times\frac{25}{3}=9259.2592593  

This is the maximum volume the box can assume.

Thus, when dimension of box is 33.3 inches × 33.3 inches ×8.3  then its volume is maximum and is 9259.26 cubic inches.

6 0
3 years ago
A rectangular prism has a length of 7 cm, a width of 4 cm, and a height of 2 1/2 cm.
BartSMP [9]
First solve the volume of the rectangular prism
V = l x w x h
where l is the length
w is the width
h is the height
V = 7 x 4 x 2.5
v = 70 cu cm

then solve the volume of the box
v = e^3
v = 0.5^3
v = 0.125

number of cubes = 70 / 0.125
number of cubes = 560 cubes
4 0
4 years ago
Read 2 more answers
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